WILL MARK BRAINLIEST

When aluminum, AlAl, metal is dipped in an aqueous solution of hydrochloric acid, HClHCl, hydrogen gas, H2H2, is produced with t

kifflom [539]

Answer:

Balanced equation: $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_{3}(aq.)+3H_{2}(g)$

Explanation:

Al is an metallic species with a standard reduction potential of -1.66 V( $E_{Al^{3+}\mid Al}^{0}=-1.66V$ ).
$H_{2}$ is present at the intermediate position in electrochemical series with a standard reduction potential of 0 V ( $E_{H^{+}\mid H_{2}}^{0}=0V$ ).

So, when Al is dipped in aqueous solution of HCl, Al is readily oxidized to produce $Al^{3+}$ whereas $H^{+}$ is reduced to $H_{2}$ .
Hence, as a whole, aqueous $AlCl_{3}$ and gaseous $H_{2}$ is produced as products.

Balanced equation: $2Al(s)+6HCl(aq.)\rightarrow 2AlCl_{3}(aq.)+3H_{2}(g)$

5 0

4 years ago

Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.

Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = $2.2 \times 10^{2}$ ml = 220 ml

Volume of 4 glass of water = $220 \times 4$ = 880 ml

We known that density of water is 1 g/ml. Therefore, calculate the mass of water as follows.

Mass of water = $880 ml \times 1 g/ml$

= 880 gm

= 0.88 Kg (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

Q = $mC \Delta T$

$\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C$

Putting the given values into the above formula as follows.

Q = $mC \Delta T$

= $0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C$

= 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b). As we know that the heat of fusion of ice is 333 J/g.

So, energy required for $8.4 \times 10^{2}$ g or 840 g is as follows.

$333 \times 840$ = 279.72 kJ

Heat capacity of water= 4.184 $J/g^{o}C$

Now, heat energy will be as follows.

Q = $4.184 \times 840 g \times 37^{o}C$

= 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

= 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ of heat.

6 0

3 years ago

During cellular respiration, plants take in _______ from the air and break down stored _______.

Zepler [3.9K]

Answer:

During cellular respiration, plants take in carbon dioxide from the air and break down stored glucose.

Explanation:

Before cellular respiration takes place in a plant, photosynthesis occurs and absorbs sunlight and carbon dioxide from the air. The process then produces oxygen and glucose, which are needed as the reactants for cellular respiration. Cellular respiration will break down the stored glucose to make energy to produce carbon dioxide and water. Then the cycle repeats itself.

7 0

4 years ago

How do you know if a reaction is exothermic

melisa1 [442]

When there is heat released

7 0

3 years ago

Read 2 more answers

HClO is a weak acid (Ka = 4.0 × 10–8) and so the salt NaClO acts as a weak base. What is the pH of a solution that is 0.028 M in

zloy xaker [14]

This photo should help

7 0

3 years ago