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nadezda [96]
3 years ago
13

When 2,4-hexadiene is protonated, a resonance-stabilized secondary allylic carbocation is formed. Draw the curved arrow notation

below that shows the movement of electrons between the two major resonance structures.

Chemistry
1 answer:
NemiM [27]3 years ago
4 0

Answer:see the image for the structure of the allylic carbocation

Explanation:

When 2,4-hexanediene is protonated at the 5-position as shown in the image, a carbonation is formed which can be stabilized by resonance. The positive charge can be found on carbon 4 or carbon 2 due to resonance of the allylic carbonation. The both structures are shown and electron movements were depicted using curved arrow notation in the structures shown in the image attached.

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calculation

Step 1: write the chemical equation for the reaction

CH3CH2CH2COOH + CH3CH2OH →  CH3CH2CH2COOCH2CH3  +H2O

step 2: find the moles of butanoic acid

moles= mass/ molar mass

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Step 3:  use the mole ratio to determine the moles of ethyl butyrate

moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3  is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875  x78/100=0.0683moles

step 4: find mass = moles x molar mass

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3 years ago
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Magnesium hydroxide is added to a solution of hydrochloric acid. A reaction occurs and magnesium chloride and water are formed.
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