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Anna11 [10]
3 years ago
15

Determine if the equation is linear. If so, graph the function.

Mathematics
1 answer:
Alexeev081 [22]3 years ago
6 0

Answer:

I don't know I'm just answering questions because i need points

Step-by-step explanation:

ehh can I get a brainless?

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Marcy is making a hooked circle-shaped rug for her mother. The circumference of the circle-shaped rug is 75.36 inches. What is t
Nesterboy [21]
     The area of the circular shaped rug would be 451.931, let me explain to you how I got this calculation.
     
     First thing you have to do is know the formula to find the area of a circle. The formula is A=pie x Rsquared, but when you look at the information provided, you dont have the radius, so you have to find it yourself. 
 
    You probably noticed that since diameter is twice the radius, the proportion between circumference and diameter is equal to π: <span>C/D = 2πR / 2R = π is the formula for the convertion of circumfrence to diameter.
</span> 
     Once you find the diameter, which should be rounded to 23.98, you will need to divide it by 2 for the radius which should give you approximatly 11.99. 
 
     Finally, you do the regular formula to find area which is A=pie x Rsquared. so you do 3.14 x (11.99 x 11.99)=451.931in.




8 0
4 years ago
Which of the following graphs represents a function?
kirza4 [7]

The third graph represents a function.

In a function, every input (x value) has <em>exactly</em> one output (y value). If even a single input has zero or two outputs, the graph does not represent a function.

A good way of testing this is using a vertical line. As you move a vertical line from left to right across a graph, it should always be touching exactly one point on the graphed line.

In this case, every graph fails this vertical line test except for the third graph, so the third graph represents a function.

8 0
2 years ago
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Kelly earns a 7% commission on the total amount of her sales. This year, she had $210,000 in sales. How much commission did Kell
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4 0
3 years ago
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
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tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Dora is purchasing a $162,000 home with a 30-year mortgage at 5.15%. What is her monthly principal and interest payment?
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