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Kruka [31]
2 years ago
8

What is the process for extracting oils

Chemistry
1 answer:
OLEGan [10]2 years ago
4 0

Answer:

Oil is extracted by three general methods: rendering, used with animal products and oleaginous fruits; mechanical pressing, for oil-bearing seeds and nuts; and extracting with volatile solvents, employed in large-scale operations for a more complete extraction than is possible with pressing.

Explanation:

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3 years ago
A solution has a [oh−] of 1 x 10−12. what is the poh of this solution? 2 7 10 12
Colt1911 [192]
POH = - log [ OH-]

pOH = - log [ 1 x 10⁻¹²]

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3 years ago
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If the enthalpy value for a reaction is negative, what does that indicate about the reaction? Please explain how you got your an
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The answer is; D

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The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding
slega [8]

Answer:

Binding\ energy=43.43\times 10^{-20}\ J

Explanation:

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E=h\nu_0+\frac {1}{2}\times m\times v^2

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\nu_0=\frac {c}{\lambda_0}

Applying the equation as:

\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2

Where,  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

c is the speed of light having value 3\times 10^8\ m/s

\lambda is the wavelength of the light being bombarded

Given, \lambda=4.00\times 10^{-7}\ m

\frac {hc}{\lambda_0} is the binding energy or threshold energy

\frac {1}{2}\times m\times v^2 is the kinetic energy of the electron emitted.  = 6.26\times 10^{-20}\ J

Thus, applying values as:

\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy

\frac{6.626\times 10^{-34}\times 3\times 10^8}{4.00\times 10^{-7}}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J

Binding\ energy=43.43\times 10^{-20}\ J

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3 years ago
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