Answer : The work done on the surroundings is, 709.1 Joules.
Explanation :
The formula used for isothermally irreversible expansion is :
where,
w = work done
= external pressure = 1.00 atm
= initial volume of gas = 1.00 L
= final volume of gas = 8.00 L
Now put all the given values in the above formula, we get :
The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.
Therefore, the work done on the surroundings is, 709.1 Joules.
Answer:
Ki = 30atmL
Kf = 30atmL
Explanation:
The following data were obtained from the question:
V1 (initial volume) = 15.0L
P1 (initial pressure) = 2atm
V2 (final volume) = 7.5L
P2 (final pressure) = 4atm
Ki (initial constant) =?
Kf (final constant) =?
Boyle's law states that PV = K
Ki = P1V1
Ki = 2 x 15 = 30atmL
Kf = P2V2
Kf = 4 x 7.5 = 30atmL
Since Ki and Kf are the same, the gas obey Boyle's law
Answer:
Electrons treated as waves
Explanation:
Answer:
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