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Ad libitum [116K]
3 years ago
9

Which lab safety rule do you think is the most important to follow in chemistry lab?

Chemistry
1 answer:
Flauer [41]3 years ago
7 0

Answer:

Practice good personal hygiene. Wash your hands after removing gloves, before leaving the laboratory, and after handling a potentially hazardous material. While working in the laboratory, wear personal protective equipment - eye protection, gloves, laboratory coat - as directed by your supervisor.

Explanation:

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What are bacteria? Chapter 7 lesson 2 AYU
Maru [420]

Answer:

a group of unicellular microorganisms

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3 years ago
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A sample of O2 gas occupies a volume of 571 mL at 26 ºC. If pressure remains constant, what would be the new volume if the tempe
Vlad1618 [11]

Answer: The new volume at different given temperatures are as follows.

(a) 109.81 mL

(b) 768.65 mL

(c) 18052.38 mL

Explanation:

Given: V_{1} = 571 mL,       T_{1} = 26^{o}C

(a) T_{2} = 5^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{5^{o}C}\\V_{2} = 109.81 mL

(b) T_{2} = 95^{o}F

Convert degree Fahrenheit into degree Cesius as follows.

(1^{o}F - 32) \times \frac{5}{9} = ^{o}C\\(95^{o}F - 32) \times \frac{5}{9} = 35^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{35^{o}C}\\V_{2} = 768.65 mL

(c) T_{2} = 1095 K = (1095 - 273)^{o}C = 822^{o}C

The new volume is calculated as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{571 mL}{26^{o}C} = \frac{V_{2}}{822^{o}C}\\V_{2} = 18052.38 mL

8 0
3 years ago
What 3 classes of compounds are elecrolytes
zvonat [6]

Answer:

i believe it is strong acids, strong bases, and salts.

Explanation:

Hope this helps : )

4 0
3 years ago
Which type of energy in the bungee cord prevents the bungee jumper from hitting the ground
Effectus [21]
Elastic potential energy
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3 years ago
Chlorine has two isotopes, 35Cl and 37Cl; 75.77 % of chlorine is 35Cl and 24.23 % is 37Cl. The atomic mass of 35Cl is 34.969 amu
storchak [24]

Answer:

35.4528731 amu

Explanation:

To appropriately get the atomic mass unit of chlorine, we can get the answer using the masses from the isotopes. This can be obtained as follows. What we do is that we multiply the percentage compositions by the masses.

Now let’s do this.

[75.77/100 * 34.969] + [24.23/100 * 36.966]

= 26.4960113 + 8.9568618 = 35.4528731

3 0
3 years ago
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