Answer:
34g of potassium chlorate.
Explanation:
A saturated solution is a solution that, under a temperature, has the maximum amount of solute possible. The maximum amount that a solvent can dissolve of a solute is called <em>solubility.</em>
<em> </em>
The solubility of potassium chlorate in water at 70°C is 34g/ 100g of water.
That means, to saturate 100g of water at 70°C you need yo add:
<h3>34g of potassium chlorate.</h3>
Answer:
7.25 x 10^47
Explanation:
1.204 x 10^24 moles*6.022 x 10^23 avogadro's number= 7.25 x 10^47
Question 1. What one factor identifies an atom as a specific element? Answer: the number of protons. Remember that the atoms of a same element have the same number of protons, and the atoms of different elements cannot have the same number of protons. That permits to order the elements according to the atomic number (number of protons) in the periodic table. Question 2.An atom of fluorine has an atomic number of 9 and an atomic mass of 19. The atom contains Answer: 9 protons, 9 electrons, and 10 neutrons : because the atomic number is the number of protons, the number of electrons must be equal to the number of protons (because the atom is neutral), and the mass number is the number or protons plus the number of neutrons: 9 protons + 10 neutrons = 19 mass number (atomic mass). Question 33.Experiments with cathode ray tubes led to a new model of the atom, sometimes called the \"plum pudding\" model, because of the discovery of the <span>. Answer. electron ... when electron was discovered JJ Thompson proposed the plum pudding model, in which the atom was a solid positively charged sphere with electrons distributed inside it.</span>
Answer:
Any device that contains electronic parts
According to this formula:
㏑(K2/K1) = Ea/R(1/T1 - 1/T2)
when K is the rate constant
Ea is the activation energy
R is the universal gas constant
and T is the temperature K
when K is doubled so K2: K1 = 2:1 & R = 8.314 J.K^-1.mol^-1
and T1 = 10 +273 = 283 k & T2 = 21 + 273 = 294 k
So by substitution:
㏑2 =( Ea / 8.314) (1/283 - 1/294 )
∴ Ea = 43588.9 J/mol = 43.6 KJ/mol
