Answer:
25 mM Tris HCl and 0.1% w/v SDS
Explanation:
A <em>10X solution</em> is ten times more concentrated than a <em>1X solution</em>. The stock solution is generally more concentrated (10X) and for its use, a dilution is required. Thus, to prepare a buffer 1X from a 10X buffer, you have to perform a dilution in a factor of 10 (1 volume of 10X solution is taken and mixed with 9 volumes of water). In consequence, all the concentrations of the components are diluted 10 times. To calculate the final concentration of each component in the 1X solution, we simply divide the concentration into 10:
(250 mM Tris HCl)/10 = 25 mM Tris HCl
(1.92 M glycine)/10 = 0.192 M glycine
(1% w/v SDS)/10 = 0.1% w/v SDS
Therefore the final concentrations of Tris and SDS are 25 mM and 0.1% w/v, respectively.
Answer:
The density in g/cm3 is 1.9333(put a line above the 3's to show it's repeating).
And no it is not gold because the density of gold in g/cm3 is 19.3.
Explanation:
Divide the mass by the volume in order to get an object's Density.
so, 23.2 divided by 1.20 mm3
=1.93333333 g/cm3
That is the density then you find out the density of gold in grams per cubic centimeter, that is 19.3 g/cm3
For example, gold will always have a density of 19.3 g/cm3; if a mineral has a density other than that, it isn't gold.
Your answer is False I think
Answer:
Explanation:
Molar mass of NaCl = (23+35.5)
Molar mass of NaCl = 58.5g/mol
Molar mass of C12H22011
= 12(12) + 22(1) + 16(11)
= 144 +22 + 176
= 342g/mol
Molarity is 1.5 M and the volume is 2 l; thus
The number of moles of NaCl will be given by;
Molarity × volume in liters
= 1.5 × 2 = 3 moles
But 1 mole of NaCl contains 58.5 g/mole
Therefore; the mass of 3 moles will be;
3 × 58.5 = 175.5 g
The mass of NaCl is therefore 175.5 g
