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3 years ago

What are some examples of Heterogeneous Catalysts?

Chemistry

1 answer:

Svetach [21]3 years ago

4 0

Catalytic converter in gasoline or diesel-fueled cars

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¿en que estado de agregacion se encuentra un cuerpo con forma y volumen propio?

xeze [42]

Answer: Um what is it?

Explanation:

3 0

2 years ago

An unknown organic compound composed of carbon, hydrogen, and oxygen was analyzed and found to be 50.84% C, 8.53% H, and the res

MariettaO [177]

In every 100g of that compund there is 50.84 g of C, 8.53 g H and (100-59.37) g = 40.63 g of O.

Step 1: Convert each element's mass in moles. To do that we need to divide each element's mass by their respective molar mass.

For Carbon.

$C = \frac{50.84}{12} = 4.24 mol$

For Hydrogen.

$H = \frac{8.53}{1} = 8.53 mol$

For Oxygen.

$O = \frac{40.63}{16} = 2.54 mol$

Step 2: Divide each of the numbers by the smallest number.

For Carbon.

$C = \frac{4.24}{2.54} = 1.7$

For Hydrogen.

$H = \frac{8.53}{2.54} = 3.36$

For Oxygen.

$O = \frac{2.54}{2.54} = 1$

Step 3: So the empirical formula will be.

$C_{1.7} H_{3.36} O_1$

But using decimal will be messy. So we multiply the numbers by 3. The right empirical formula will be.

$C_{5} H_{10} O_3$

7 0

3 years ago

6.626 × 10⁻³⁴ × 7.08× 10¹⁴

PolarNik [594]

The answer is 4.69 x 10⁻¹⁹ I hope this helped!

3 0

3 years ago

1 lb of CO2 occupies 0.6 ft^3 at a pressure of 200 psi. Determine the temperature of the system.

Anarel [89]

<u>Answer:</u> The temperature of the system is 273 K

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of carbon dioxide = 1 lb = 453.6 g (Conversion factor: 1 lb = 453.6 g)

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

$\text{Moles of carbon dioxide}=\frac{453.6g}{44g/mol}=10.31mol$

To calculate the temperature of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = Pressure of carbon dioxide = 200 psia = 13.6 atm (Conversion factor: 1 psia = 0.068 atm)

V = Volume of carbon dioxide = $0.6ft^3=16.992L$ (Conversion factor: $1ft^3=28.32L$ )

n = number of moles of carbon dioxide = 10.31 mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the system = ?

Putting values in above equation, we get:

$13.6atm\times 16.992L=10.31mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times T\\\\T=273K$

Hence, the temperature of the system is 273 K

8 0

3 years ago

NEED HELP QUICK!!!!!!!!!!!!!!

denis23 [38]

The compounds that are produced upon this combustion reaction would be Carbon Dioxide and water.

CO2 = Carbon and Oxygen
H2O = Hydrogen and Oxygen.

The exact molecular amounts or moles can be determined by balancing this combustion reaction.

3 0

3 years ago

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