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Svetlanka [38]
3 years ago
14

What are some examples of Heterogeneous Catalysts?

Chemistry
1 answer:
Svetach [21]3 years ago
4 0
Catalytic converter in gasoline or diesel-fueled cars
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What are eight elements named after towns
maxonik [38]
1. Berkelium(Berkeley, CA) 2. Dubnium(Dubna, Russia) 3. Darmstaditum (Darmstadt, Germany) 4. Erbium(Ytterby, Sweden) 5. Strontium(Strontian, Scotland) 6. Terbium(Ytterby, Sweden) 7. Yttebium(Ytterby, Sweden) 8. Yttrium(Ytterby, Sweden)
5 0
3 years ago
Calculate the grams of sodium hydroxide formed when 2.24 moles of sodium oxide react with water
Romashka [77]
The balanced reaction is 
Na2O + H2O --> 2NaOH

If 2.24 moles of sodium oxide react, that means 4.48 moles of NaOH is formed as it is a 1 to 2 stoichiometric relationship.

Now we multiply by the molar mass to get grams.

4.48 moles NaOH * (39.997 grams/1 mole) = 179.2 grams

Your answer is 179. grams.
6 0
3 years ago
A 25 liter balloon holding 1.5 moles of carbon dioxide leaks. If we are able to determine that 0.9 moles of carbon dioxide escap
ad-work [718]

Answer:

10 Litre

Explanation:

Given that ::

v1 = 25L ; n1 = 1.5 mole ; v2 =? ; n2 = (1.5-0.9) = 0.6 mole

Using the relation :

(n2 * v1) / n1 = (n2 * v2) / n2

v2 = (n2 * v1) / n1

v2 = (0.6 mole * 25 Litre) / 1.5 mole

v2 = 15 / 1.5 litre

v2 = 10 Litre

3 0
3 years ago
Discribe how continents and oceans are carried on tectonic plates
Vanyuwa [196]
This question seems to be very basic .the ocean is above the plate, the plate material is heavier than water (it being rock). That's pretty much all of it. The plates grind a little and new land pushes up at plate boundaries but this does not seem to be related. The heavier material is below and the lighter above, those being rock and water respectively.
hope this helped u
7 0
3 years ago
In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?
sweet [91]

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99   u

1 H   = 1 × 1.008 u =    1.008 u

1 C   = 1 × 12.01  u =  12.01    u

3 O = 3 × 16.00 u =  <u>48.00  u </u>

               TOTAL =  84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

4 0
3 years ago
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