When 10 grams of copper and 10 grams of iodine are mixed, what is the
2 answers:
Answer:
15 grams
Explanation:
Mass of Cu = 10 g
Molar mass of Cu = 63.546 g/mol
Moles of Cu = = 0.1574
Mass of I₂ = 10 g
Molar mass of I₂ = 253.8 g/mol
Moles of I₂ = = 0.04
I₂ here is the limiting reactant as it has the least number of moles.
Based on the balanced equation,
1 mole of I₂ = 2 moles of CuI
0.04 mole of I₂ = 0.08 moles of CuI
Molar mass of CuI = 190.45 g/mol
Mass of CuI = 0.08 moles x 190.45 g/mol = 15.236 g
You might be interested in
Answer:
28500 years
Explanation:
Applying,
A = A'()............... Equation 1
Where A = Original mass of Carbon-14, A' = Final mass of carbon-14 after decaying, x = total time, y = half-life.
From the question,
Given: A = 1 g, A' = 31.3 mg = 0.0313 g, y = 5700 years.
Substitute these values into equation 1
1 = 0.0313()
= 1/0.0313
= 31.95
≈ 32
≈ 2⁵
Equating the base and solve for x
x/5700 ≈ 5
x ≈ 5×5700
x ≈ 28500 years