Answer:
15 grams
Explanation:
Mass of Cu = 10 g
Molar mass of Cu = 63.546 g/mol
Moles of Cu = = 0.1574
Mass of I₂ = 10 g
Molar mass of I₂ = 253.8 g/mol
Moles of I₂ = = 0.04
I₂ here is the limiting reactant as it has the least number of moles.
Based on the balanced equation,
1 mole of I₂ = 2 moles of CuI
0.04 mole of I₂ = 0.08 moles of CuI
Molar mass of CuI = 190.45 g/mol
Mass of CuI = 0.08 moles x 190.45 g/mol = 15.236 g
Answer:
-205.7kj
Explanation:
Now adding reaction 2 and twice of reaction 3 and reverse of reaction 1, we get the enthalpy of the reaction.
The expression for enthalpy for the following reaction will be,
where,
n = number of moles
Now put all the given values in the above expression, we get:
Therefore, the enthalpy of the following reaction is, -205.7kj
