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3 years ago

Given AE = EC, for what value of x is quadrilateral ABCD a parallelogram?

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

Each side of the Rhombus is equal to 4x

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Determine if the function is one-to-one. A parabola is shown facing up with a vertex of 2.5, -6

Elina [12.6K]

ANSWER

It is not one-to-one function

EXPLANATION

A one-to-one function must pass the horizontal line test.

The graph described in the question looks like the one in the attachment.

A horizontal line drawn in red cuts the graph at more than one point.

Therefore the parabola shown facing up with a vertex $(2.5, -6)$ is not a one-to-one function.

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3 years ago

The hypotenuse of a right triangle measures 16 cm and one of its legs measures 11 cm.

Zarrin [17]

Answer:

11.6cm

Step-by-step explanation:

a^2+b^2=c^2

11^2+b^2=16^2

121+b^2=256

b^2=135

b=11.6

6 0

2 years ago

Question 8

Lelechka [254]

Answer:

$695.88

Step-by-step explanation:

579 + 32 = 611

8% of 611 = 48.88

611 + 48.88 = 659.88

Stay safe! <3

6 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are without replacement.

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

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3 years ago

PLS HELP ASAP ILL GIVE BRAINLKEST PLS THANKS ASAP PLS

kherson [118]

Answer
2nd one
(2,-2) ordered pair -4 y-intercept

7 0

3 years ago

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