“Weight of the wrench” on “the moon” is “6.07 kg”.
<u>Explanation</u>:
Weight of the wrench is 5.24 N
Weight of the wrench in kilograms = W × g
Taken “g” on the moon is 

Weight of the wrench in kilograms is 51.352 kg.
Formula to calculate weight of the object on the moon is

Substitute the values given,


= 6.07 kg
Therefore, weight of the wrench on the moon is 6.07 kg.
Answer:
It will be the same for both
Explanation:
from this question we have one similarity between these two spheres.
- they are both made from the same material,
The difference between both spheres is that:
- one of the spheres has its diameter to be twice as large as that of the other one.
We are to say the sphere with the greater bulk modulus.
If the material is the same thenthe Bulk modulus is also the same. It is not dependent on the material since it is a constant for that materia
Therefore the correct answer is:
It will be the same for both spheres.
Answer:

Explanation:
The kinetic energy possessed by particles will be

where,
M is the mass of the particle (7920938.3 MeV/c²)
c is the speed of the light
Also,
energy of the proton particle = 
where,
v is the velocity
m_p is the mass of the proton (938.3 MeV/c²)
since the energy is equal
thus,

or
![1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2](https://tex.z-dn.net/?f=1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%3D%5B%5Cfrac%7B2m_p%7D%7BM%7D%5D%5E2)
substituting the values in the above equation, we get
![1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2](https://tex.z-dn.net/?f=1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%3D%5B%5Cfrac%7B2%5Ctimes%20938.3%20%7D%7B7920%7D%5D%5E2)
or

Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>
Hello kiddio!
Most of the mass<span> of atom is in a dense positively charged </span>nucleus<span>. Most of the volume of an atom is in an empty space in which negatively charged electrons move around the </span>nucleus<span>.
</span>
Have a nice day
Answer:
4.
Explanation:
Given,
frequency of standing wave = 603 Hz
length of string,L = 1.33 m
speed of the wave, v = 402 m/s
number of antinodes = ?
Wavelength of the standing wave



Number of anti nodes in the standing wave



n =3.97= 4.
Number of antinodes is equal to 4.