Question

What is the second lowest resonant frequency for a 0.7 m long organ pipe closed at one end? e) 515 Hz d) 368 Hz c) 405 Hz b) 429 Hz a) 322 Hz

Answer 1

Answer:

(d) 368 Hz

Explanation:

The resonance frequency of one closed end pipe is given by $f=\frac{nv}{4L}$ where n =1,3,5,7------------

Here we are talking about second lowest resonant frequency so n=3

The speed of sound v = 343 m/sec

Length of pipe L =0.7 m

So $f=\frac{nv}{4L}=\frac{3\times 343}{4\times 0.7}=367.5\ Hz$

Which is closest to 368 Hz so option (d) will be the correct answer