Answer:
heat of combustion is 23258.17 J/g or 23.258 kJ/g
Explanation:
given data
temperature range = 20.00°C to 23.55°C
so temperature change is = 3.55°C
heat capacity = 403 J/K
so here heat absorbed by calorimeter is
heat absorbed = heat capacity × change temperature
heat absorbed = 403 × 3.55
heat absorbed = 1430.65 J
and
volume of water is = 2.550 L = 2550 mL
and water density = 1.00 g/mL
so mass of water = volume × density
mass of water = 2550 × 1
mass of water = 2550 g
and
specific heat capacity for water is here = 4.184 J/g-°C
and temperature change = 3.55°C
so heat absorbed by water = mass × specific heat × temperature change
heat absorbed by water = 2550 × 4.184 × 3.55 = 37875.66 J
so
so heat absorbed by water and calorimeter is 1430.65 J + 37875.66 J
heat absorbed by water and calorimeter is 39306.31 J
so this heat give combustion 1.690 g fuel
so for 1 gram heat given =
heat of combustion is 23258.17 J/g or 23.258 kJ/g