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vova2212 [387]
3 years ago
15

Calculate the length between the following points using the distance formula

Chemistry
1 answer:
Aloiza [94]3 years ago
4 0

Answer:

If i have 2 apples and 6 bannanas how many ansers do i get for 7xy

Explanation:

6.4

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stiks02 [169]

Answer:

8.21

Explanation:

3 0
3 years ago
Mr. Rutherford's chemistry class was collecting data in a neutralization study. Each group had 24 test tubes to check each day f
ycow [4]
I’m pretty sure it is A at least that’s what we did at our school to test this
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2H2 + O2 → 2H2O
pantera1 [17]
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles

moles of O2 is half
so 40.04 x 0.5
20.02moles

grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g

6 0
3 years ago
Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.
Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = 2.2 \times 10^{2} ml = 220 ml

Volume of 4 glass of water = 220 \times 4 = 880 ml

We known that density of water is 1 g/ml.  Therefore, calculate the mass of water as follows.

       Mass of water = 880 ml \times 1 g/ml

                               = 880 gm

                               = 0.88 Kg               (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

            Q = mC \Delta T

\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C

Putting the given values into the above formula as follows.

         Q = mC \Delta T

             = 0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C

             = 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b).      As we know that the heat of fusion of ice is 333 J/g.

So, energy required for 8.4 \times 10^{2} g or 840 g is as follows.

          333 \times 840 = 279.72 kJ

Heat capacity of water= 4.184 J/g^{o}C

Now, heat energy will be as follows.

           Q = 4.184 \times 840 g \times 37^{o}C

               = 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

                                                  = 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ  of heat.

6 0
4 years ago
Please help!! I'll name you brainliest!!
Illusion [34]

Answer:

H20 Covalent bond

Kl Ionic bond

NaBr ionic bond

Co2 Covalent bond

MgCl2 ionic bond

HCl Covalent bond

Explanation:

4 0
3 years ago
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