Answer:
The probability that a person with restless leg syndrome has fibromyalgia is 0.183.
Step-by-step explanation:
Denote the events as follows:
<em>F</em> = a person with fibromyalgia
<em>R</em> = a person having restless leg syndrome
The information provided is as follows:
P (R | F) = 0.33
P (R | F') = 0.03
P (F) = 0.02
Consider the tree diagram attached below.
Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:
![P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}](https://tex.z-dn.net/?f=P%28F%7CR%29%3D%5Cfrac%7BP%28R%7CF%29P%28F%29%7D%7BP%28R%7CF%29P%28F%29%2BP%28R%7CF%27%29P%28F%27%29%7D)
![=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%280.33%5Ctimes%200.02%29%7D%7B%280.33%5Ctimes%200.02%29%2B%280.03%5Ctimes%200.98%29%7D%5C%5C%5C%5C%3D%5Cfrac%7B0.0066%7D%7B0.0066%2B0.0294%7D%5C%5C%5C%5C%3D0.183333%5C%5C%5C%5C%5Capprox%200.183)
Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.
Answer:
(2x+3)(x+1)
Step-by-step explanation:
1 foot = 12 inch so 6 feet = 6*12 inch
6 feet = 72 inch
The height of the person in inch is = 72+1 = 73 inch
1 meter.............39.37 in
x meters.......... 73 in
x = 73/39.37 = 1.85 meters
Answer:
1.92%
Step-by-step explanation:
The probability for first case, picking a queen out of deck, will be:
![\frac{4}{52}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B52%7D)
as there will be 4 queens in a deck, one of each suit.
For the second pick, the probability of picking a diamond card, will be:
![\frac{13}{52}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B52%7D)
here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).
Thus the net probability for both cases will be:
![P = \frac{4}{52} * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%](https://tex.z-dn.net/?f=P%20%3D%20%5Cfrac%7B4%7D%7B52%7D%20%20%2A%20%5Cfrac%7B13%7D%7B52%7D%5C%5C%20P%20%3D%20%5Cfrac%7B1%7D%7B52%7D%5C%5C%20P%20%3D%200.01923%5C%5CP%20%3D%201.923%5C%25%5C%5C%5C%5CP%20%3D%201.92%5C%25)
Thus total probability for the combined two cases will be 1.92%