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Mashcka [7]
3 years ago
11

What is the future value of $1,600 in 17 years assuming an interest rate of 10 percent compounded semiannually?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0
Let
F--------------------> future value
P--------------------> present value 
r --------------------> interest rate per year
m ------------------ > number of compounding periods per year
t -------------------->  time in years. 
we know that
P=$1,600
<span>t=17 years
m=2
r=10%------> 0.10

F=P(1+i)</span><span>^n
</span><span>where
i=r/m   ---------> 0.10/2=0.05
and
n=m*t------------> 2*17=34

</span>F=1600*(1+0.05)^34=8405.36
<span>
the answer is $</span>8405.36<span>

</span>
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The mass of a tiger at a zoo is 235 kilograms. Randy's cat has a mass of 5,000 grams. How many times greater is the mass of tige
ANTONII [103]
Solutions 

We know that <span>the mass of a tiger at a zoo is 235 kilograms. Randy's cat has a mass of 5,000 grams. To solve the problem we have to convert 235 kilograms into grams. 

</span>235 kilograms = 235000 grams 

<span>Randy's cat has a mass of 5,000 grams 
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Randy's cat = <span>5,000 grams 
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Tiger = <span>235000 grams  
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Our next step is to subtract 5000 from <span>235000 grams  
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235000 grams  - <span>5000 grams = 230000 
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3 years ago
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Consider the polynomial P(x)=x⁴+3x³-28x²-36x+144. Write the equation of P in factored form.
garik1379 [7]

Answer:

P(x)=(x-2)(x-4)(x+3)(x+6)

Step-by-step explanation:

Given: P(x)=x⁴+3x³-28x²-36x+144

It is a polynomial with degree 4.

It should maximum four factor.

Hit and trial error method.

Put x = 2 into P(x)

P(2)=2⁴+3×2³-28×2²-36×2+144

P(2) = 0

So, x-2 would be factor of P(x)

Now divide x⁴+3x³-28x²-36x+144 by x-2 to get another factors

(x^4+3x^3-28x^2-36x+144)\div (x-2) = x^3+5x^2-18x-72

P(x)=(x-2)(x^3+5x^2-18x-72)

Put x = 4

P(4) = 0

now divide x^3+5x^2-18x-72 by x-4

(x^3+5x^2-18x-72)\div (x-4) = x^2+9x+18

P(x)=(x-2)(x-4)(x^2+9x+18)

Now factor x^2+9x+18

\Rightarrow x^2+9x+18

\Rightarrow (x+6)(x+3)

Complete factor of P(x)

P(x)=(x-2)(x-4)(x+3)(x+6)

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