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3 years ago

What is the future value of $1,600 in 17 years assuming an interest rate of 10 percent compounded semiannually?

1 answer:

5 0

Let
F--------------------> future value
P--------------------> present value
r --------------------> interest rate per year
m ------------------ > number of compounding periods per year
t --------------------> time in years.
we know that
P=$1,600
t=17 years
m=2
r=10%------> 0.10

F=P(1+i)^n
where
i=r/m ---------> 0.10/2=0.05
and
n=m*t------------> 2*17=34

F=1600*(1+0.05)^34=8405.36

the answer is $8405.36

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

The probability that a company will launch the product A and B are 0.45 and 0.60 respectively, in main while, probability that b

Brrunno [24]

Answer:

a) what is the probability that Neither will of these products launch ?

= 0.30

b) At least one product will be launched ?

= 0.70

Step-by-step explanation:

From the above question, we have the following information:

P(A) = 0.45

P(B) = 0.60

P(A ∩ B) = P(A and B) launching = 0.35

Step 1

We find the Probability that A or B will launch

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

a) what is the probability that Neither will of these products launch ?

1 - Probability ( A or B will launch)

= 1 - 0.70

= 0.30

b)At least one product will be launched?

This is equivalent to the probability that A or B will be launched

P (A ∪ B) = P(A) + P(B) - P(A ∩ B)

= 0.60 + 0.45 - 0.35

= 1.05 - 0.35

= 0.70

3 0

3 years ago

A horse walks around a circular track while its trainer stands in the center. The trainer is 14 feet from the horse at all times

max2010maxim [7]

The horse traveled 439.6 feet after walking around the track 5 times

Solution:

Given that, horse walks around a circular track while its trainer stands in the center

The trainer is 14 feet from the horse at all times

Therefore, radius of circular track = 14 feet

The circumference of circle is the distance traveled by horse for 1 lap

The circumference of circle is given as:

$C = 2 \pi r$

Where, "r" is the radius and $\pi$ is a constant equal to 3.14

$C = 2 \times 3.14 \times 14\\\\C = 87.92$

Thus the distance traveled by horse for one time in circular track is 87.92 feet

About how far had the horse traveled after walking around the track 5 times?

Multiply the circumference by 5

$distance = 5 \times 87.92\\\\distance = 439.6$

Thus the horse traveled 439.6 feet after walking around the track 5 times

5 0

3 years ago

NEED HELP ASAP! WILL GIVE BRAINLIEST

Tom [10]

Answer:

Part A

x = liters (the milk and water)

0.2 x + 1 = x

Part B

0.2 x + 1 = x

0.8 x = 1

x = 1 : 0.8 = 1.25 liters

Milk

1.25 x 0.2 = 0.25

4 0

3 years ago

an engineer estimates that 30% of gasoline is used efficiently by a car. how many gallons,out of 20 gallons, are used efficientl

juin [17]

We need to find 30% of 20 gallons.

1) We can write a proportion

20 gallons ---- 100%

x gallons --------30%

x = 20*30/100 = 6 gallons

2) Or we can write 30% as decimal.

30% = 30/100 = 0.3

0.3 of 20 = 0.3*20 =6 gallons

Answer 6 gallons are used efficiently.

3 0

3 years ago