Answer: Elements in the last period are radioactive.
Explanation:
The anode is the electrode where the oxidation occurs.
Cathode is the electrode where the reducction occurs.
Equations:
Mn(2+) + 2e- ---> Mn(s) Eo = - 1.18 V
2Fe(3+) + 2e- ----> 2 Fe(2+) 2Eo = + 1.54 V
The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.
Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72
Answer: 2.72 V
Is this an actual question?
Answer:
36 atoms
Explanation:
- C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy
The reactants are in the left side of the equation. <u>First we determine how many atoms are there in the C₆H₁₂O₆ molecule</u>:
- 6 C atoms + 12 H atoms + 6 O atoms = 24 atoms in total
There are two atoms in a O₂ molecule, and there are 6 O₂ molecules in the equation:
- 2 * (6 O atoms) = 12 atoms in total
The total number of atoms in the reactants is
