Answer:
a) 0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b) 0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c) Instantaneous rate of the reaction at t=800 s :
Instantaneous rate : 
Explanation:
Average rate of the reaction is given as;
a.) The average reaction rate between 0.0 s and 1500.0 s:
At 0.0 seconds the concentration was = 
At 1500.0 seconds the concentration was = 
![R_{avg]=-\frac{0.016 M-0.184 M}{1500.0 s-0.0 s}=0.000112 M/s](https://tex.z-dn.net/?f=R_%7Bavg%5D%3D-%5Cfrac%7B0.016%20M-0.184%20M%7D%7B1500.0%20s-0.0%20s%7D%3D0.000112%20M%2Fs)
0.000112 M/s is the average reaction rate between 0.0 seconds and 1500.0 seconds.
b.) The average reaction rate between 200.0 s and 1200.0 s:
At 0.0 seconds the concentration was = 
At 1500.0 seconds the concentration was = 
![R_{avg]=-\frac{0.019 M-0.129M}{1200.0s-200.0s}=0.00011 M/s](https://tex.z-dn.net/?f=R_%7Bavg%5D%3D-%5Cfrac%7B0.019%20M-0.129M%7D%7B1200.0s-200.0s%7D%3D0.00011%20M%2Fs)
0.00011 M/s is the average reaction rate between 200.0 seconds and 1200.0 seconds.
c.) Instantaneous rate of the reaction at t=800 s :
At 800 seconds the concentration was = 
Instantaneous rate :
C. (-2,-2) is the answer.
<u>Explanation:</u>
When we reflect a point (x, y) across the y-axis, after the reflection, the y-coordinate tends to be the same, however the x-coordinate is changed into its opposite sign.
Here U(2,-2) is reflected across the y-axis then,
the y-coordinate -2 remains the same and the x-coordinate is transformed into its opposite that is the sign of the x-coordinate will be changed as -2.
So the new coordinates of U after reflection will be (-2,-2).
Answer:
247.2g
Explanation:
Using the general gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the information in this question, a fuel tank contains 150. L (V) of H2 gas at 20.0 atm (P) at 25.0˚C (T)
Temperature = 25°C = 25 + 273 = 298K
Using PV = nRT
20 × 150 = n × 0.0821 × 298
3000 = 24.4658n
n = 3000/24.4658
n = 122.62
n = 122.6mol
Using the formula, mole = mass/molar mass, to find the mass of H2 gas.
Molar mass of H2 = 1.008(2)
= 2.016g/mol
122.6 = mass/2.016
mass = 122.6 × 2.016
mass = 247.2g.
