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stealth61 [152]
3 years ago
14

Help me please I need to pass my exam

Chemistry
1 answer:
Troyanec [42]3 years ago
8 0

Answer:

I think it is 1115 kJ but I don't see the answer

Explanation:

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How many moles of ammonia can be formed from 4.0 mol H2
Bess [88]

Answer: 1. 2.7 moles  of ammonia are formed

2. 12.0 moles  of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

N_2+3H_2\rightarrow 2NH_3

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form =\frac{2}{3}\times 4.0=2.7moles of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by  =\frac{3}{2}\times 8.0=12.0moles of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with =\frac{1}{3}\times 6.0=2.0moles of nitrogen

3 0
2 years ago
Plant Cell
musickatia [10]

Answer:

it's the chloroplast but I'm not sure which on is it it might be the F.

6 0
2 years ago
(Please answer ASAP) Describe in your own words A.) what does Inert mean? B.) why are noble gases Inert (include an explanation
Alex_Xolod [135]
Inert means unreactive in nature or un reactive in there normal or natural state
and noble gas has there outermost shell electron filled up they complete there duplet or oclet valency state that why there inert in there natural state
4 0
3 years ago
Prandtl number in heat transfer analogues to which dimension less number in mass transfer. a) Schmidt number b) Sherwood number
Cloud [144]

Answer:

a) Schmidt number

Explanation:

Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.

Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.

P_r = \frac{\nu}{\alpha}

Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.

S_c= \frac{\nu}{\nu_{AB}}

5 0
2 years ago
Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
34kurt
To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
O = 20.35 g / 16 g/mol = 1.27 mol

C = 5.72 mol / 1.27 mol = 5
H = 10.79 mol / 1.27 mol = 8
O = 1.27 mol / 1.27 mol = 1

C5H8O
6 0
3 years ago
Read 2 more answers
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