Answer:
17
Step-by-step explanation:
Here in this question for finding the numbers that will divide 398, 436 and 542 leaving remainder 7, 11 and 15 respectively we have to first subtract the remainder of the following. By this step we find the highest common factor of the numbers.
And then the required number is the HCF of the following numbers that are formed when the remainder are subtracted from them.
Clearly, the required number is the HCF of the numbers 398−7=391,436−11=425, and, 542−15=527
We will find the HCF of 391, 425 and 527 by prime factorization method.
391=17×23425=52×17527=17×31
Hence, HCF of 391, 4250 and 527 is 17 because the greatest common factor from all the numbers is 17 only.
So we can say that the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively is 17.
Note: - whenever we face such a type of question the key concept for solving this question is whenever in the question it is asking about the largest number it divides. You should always think about the highest common factor i.e. HCF. we have to subtract remainder because you have to find a factor that means it should be perfectly divisible so to make divisible we subtract remainder. because remainder is the extra number so on subtracting remainder it becomes divisible.
Answer:
The solutions are π/4, 3π/4,5π/4,7π/4
Step-by-step explanation:
The given equation is
6sin²(x) = 3
Divide by 6 to get:
This implies that;
If
in the first quadrant
in the second quadrant.
If
in the third quadrant
Answer: the length is 8
Step-by-step explanation:
Answer:
Yes and the answer is 16/5
Step-by-step explanation:
Find the reciprocal of the divisor
Reciprocal of 1/6 : 6/1
Now, multiply it with the dividend
8/15 ÷ 1/6 = 8/15 × 6/1
And after that you get 48/15 but after reducing the fraction, the answer is 16/5. ( In mixed form, 3 1/5 )
I hope this helps and I am a middle school student answering this question.
Multiply and when u get yo answer, divide to get your answer
