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Bess [88]
2 years ago
12

Find the two values that are both 6 units away from 3.

Mathematics
1 answer:
MrMuchimi2 years ago
4 0
3 +6=9 and 3-6 =-3. that’s all you need to do
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Please help me out!!
d1i1m1o1n [39]
Can do.

Arc length = radius * theta.
S=r*theta

Convert 73° to radians.
(73°)*(pi/180)
73°=1.274rad


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8 0
3 years ago
Find the equation of the line between (7,−9) and (5,6) in slope intercept form.
poizon [28]
Set y=ax+b pass (7,-9) (5,6)
=》-9=7a+b
6=5a+b
=》2a=-15
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5 0
3 years ago
Read 2 more answers
Analyze the asymptotes of the function.
koban [17]

Answer:

vertical asymptote at x=-1

horizontal asymptote at y=0

Step-by-step explanation:

y=\frac{1}{x+1}

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x+1=0 (subtract 1 from both sides)

x=-1

So, vertical asymptote at x=-1

To find horizontal asymptote we look at  the degree of both numerator and denominator

there is no variable at the numerator , so degree of numerator =0

degree of denominator =1

When the degree of numerator is less than the degree of denominator

then horizontal asymptote at y=0

5 0
3 years ago
Please answer asap <br> What is the value of x in the equation 3(2x + 4) = −6?
nydimaria [60]
First divide 3 both side
Than move 4 to another side
Than divide by 2
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3 years ago
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ANTONII [103]
Integers are always rational




6 0
3 years ago
Read 2 more answers
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