Answer with Explanation:
Newton's laws are applicable for inertial frames of reference which is a frame which is not accelerating when seen from the observer standing on earth.
For the person as he presses the brakes his frame is a decelerating frame of reference hence he cannot apply the newtons laws of motion as they are in their original form but if he analyses the motion he has to apply a correction known as pseudo-force on the object he is analyzing. Pseudo Force has no basis in newton's laws but are a correction that needs to be applied if he wishes to analyse the motion from non inertial frame of reference
While as a person standing on earth outside the car since his frame is an inertial frame of reference he can apply newton's laws of motion without any correction.
For this case, the first thing you should do is define a reference system.
Once the system is defined, we must follow the following steps:
1) Do the sum of forces in a horizontal direction
2) Do the sum of forces in vertical direction
The forces will be balanced if for each direction the net force is equal to zero.
The forces will be unbalanced if for each direction the net force is nonzero.
Answer:
Add the forces in the horizontal and vertical directions separately.
Answer:
Amp – an ampere a the unit for measuring electricity. The rate at which electricity flows is measured as an electric current. The electric current is measured in Amps.
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Answer:
(a) 2.33 A
(b) 15.075 V
Explanation:
From the question,
The total resistance (Rt) = R1+R2 = 3.85+6.47
R(t) = 10.32 ohms.
Applying ohm's law,
V = IR(t)..........equation 1
Where V = Emf of the battery, I = current flowing through the circuit, R(t) = combined resistance of both resistors.
Note: Since both resistors are connected in series, the current flowing through them is the same.
Therefore,
I = V/R(t)............. Equation 2
Given: V = 24 V, R(t) = 10.32 ohms
Substitute these values into equation 2
I = 24/10.32
I = 2.33 A.
Hence the current through R1 = 2.33 A.
V2 = IR2.............. Equation 3
V2 = 2.33(6.47)
V2 = 15.075 V
