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solniwko [45]
3 years ago
9

The first confirmed detections of extrasolar planets occurred in ____________. The first confirmed detections of extrasolar plan

ets occurred in ____________. the mid-17th century the mid-20th century the 1990s 2009
Physics
1 answer:
nirvana33 [79]3 years ago
4 0

Answer:

1992 (Early 1990s)

Explanation:

First of all, i would like to define an extrasolar planet as a planet that orbits a start that is not our own.

The first confirmed detections of extrasolar planets occured in the early 1990s (specifically 1992, some say 1995). The name of the first extrasolar planet is widely believed to be called Dimidium or 51 Pegasi b.  

Extrasolar were searched by monitoring stars for slight dimming that might occur as unseen planets pass in front of them.

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Solve for A if F=MA and F=100 and M=25?
inn [45]

Answer:

<h3>\boxed{ \boxed{ \bold{A = 4}}}</h3>

Explanation:

Given,

F = 100 , M = 25

Now, let's find the value of A

\sf{F = MA}

plug the values

⇒\sf{100 = 25 A}

Swap the sides of the equation

⇒\sf{25A = 100}

Divide both sides of the equation by 25

⇒\sf{ \frac{25A}{25}  =  \frac{100}{25} }

Calculate

⇒\sf{A = 4}

Hope I helped!

Best regards!!

5 0
3 years ago
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What step did Mendel take to be sure that his pea plants did not self-pollinate?
Ipatiy [6.2K]

Answer:

it is made up of some theory

Explanation:

it is an artificial pollination

8 0
3 years ago
HELPPP PLEASEEEEE, BRIANLEST WILL BE GIVEN ON CORRECT!​
myrzilka [38]

Answer:

a. 25000J or 25KJ

b.2500w

Explanation:

a. since we say work is force applied in the same line or straight line

<em>W=</em><em>F(</em><em>newtons </em><em>)</em><em>*</em><em>D(</em><em>metres</em><em>)</em><em> </em>

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4 0
3 years ago
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What is capacitance?
WARRIOR [948]

capacitance of any given capacitor is given by the formula,

C=Q/V

where C=capacitance,Q= charge and V=voltage

therefore from the formula capacitance is charge per unit voltage.

4 0
3 years ago
A weightlifter lifts a 32 kg barbell a distance of 0.1 m in 0.83 s. How much power is demonstrated by the lift?
In-s [12.5K]
To find power, you have to find work first.

Given :
F = 32kg —> 313.6 N
d = 0.1m
Work = Fd
= (313.6)(0.1)
= 31.36

P=W/t
=(31.36)/(0.83)
≈ 38 W

7 0
1 year ago
Read 2 more answers
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