The potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
<h3>
What is the energy in a capacitor?</h3>
The energy stored in a capacitor is an electrostatic potential energy.
It is related to the charge(Q) and voltage (V) between the capacitor plates.
It is represented as 'U'.
<h3>
How to determine the potential difference</h3>
Formula:
Potential difference, V is the ratio of the charge to the capacitance of a capacitor.
It is calculated using:
V = Q ÷ C
Where Q = charge 5 × 10∧-5C and C = capacitance 10∧-9
Substitute the values into the equation
Potential difference, V = 5 × 10∧-5 ÷ 10∧-9 = 5 × 10∧4 volts
<h3>
How to determine the energy stored</h3>
Formula:
Energy, U = 1 ÷ 2 (QV)
Where Q= charge and V = potential difference across the capacitor
Energy, U = 1 ÷ 2 ( 5 × 10∧-5 × 5 × 10∧4)
= 0.5 × 25 × 10∧-1
= 0.5 × 2.5
= 1. 25 Joules
Therefore, the potential difference across the capacitor is 5 × 10∧4 volts and the energy stored in it is 1. 25 Joules
Learn more about capacitance here:
brainly.com/question/14883923
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Answer:
1. True WA > WB > WC
Explanation:
In this exercise they give work for several different configurations and ask that we show the relationship between them, the best way to do this is to calculate each work separately.
A) Work is the product of force by distance and the cosine of the angle between them
WA = W h cos 0
WA = mg h
B) On a ramp without rubbing
Sin30 = h / L
L = h / sin 30
WB = F d cos θ
WB = F L cos 30
WB = mf (h / sin30) cos 30
WB = mg h ctan 30
C) Ramp with rubbing
W sin 30 - fr = ma
N- Wcos30 = 0
W sin 30 - μ W cos 30 = ma
F = W (sin30 - μ cos30)
WC = mg (sin30 - μ cos30) h / sin30
Wc = mg (1 - μ ctan30) h
When we review the affirmation it is the work where there is rubbing is the smallest and the work where it comes in free fall at the maximum
Let's review the claims
1. True The work of gravity is the greatest and the work where there is friction is the least
2 False. The job where there is friction is the least
3 False work with rubbing is the least
4 False work with rubbing is the least
Answer:
The current is
Explanation:
From the question we are told that
The radius of the loop is ![r = 6 \ cm = 0.06 \ m](https://tex.z-dn.net/?f=r%20%3D%20%206%20%5C%20cm%20%20%3D%200.06%20%5C%20m)
The earth's magnetic field is ![B_e = 0.7G= 0.7 G * \frac{1*10^{-4} T}{1 G} = 0.7 *10^{-4} T](https://tex.z-dn.net/?f=B_e%20%3D%20%200.7G%3D%20%200.7%20%20G%20%2A%20%5Cfrac%7B1%2A10%5E%7B-4%7D%20T%7D%7B1%20G%7D%20%20%3D%200.7%20%2A10%5E%7B-4%7D%20T)
The number of turns is ![N =1](https://tex.z-dn.net/?f=N%20%20%3D1)
Generally the magnetic field generated by the current in the loop is mathematically represented as
![B = \frac{\mu_o * N * I}{2 r }](https://tex.z-dn.net/?f=B%20%20%3D%20%20%5Cfrac%7B%5Cmu_o%20%20%2A%20N%20%20%2A%20%20I%7D%7B2%20r%20%7D)
Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth
![B = B_e](https://tex.z-dn.net/?f=B%20%20%3D%20%20B_e)
=> ![B_e = \frac{\mu_o * N * I }{ 2 * r}](https://tex.z-dn.net/?f=B_e%20%3D%20%20%5Cfrac%7B%5Cmu_o%20%20%2A%20%20N%20%20%2A%20%20I%20%20%7D%7B%202%20%2A%20r%7D)
Where
is the permeability of free space with value ![\mu _o = 4\pi * 10^{-7} N/A^2](https://tex.z-dn.net/?f=%5Cmu%20_o%20%20%3D%20%20%204%5Cpi%20%2A%2010%5E%7B-7%7D%20N%2FA%5E2)
![0.7 *10^{-4}= \frac{ 4\pi * 10^{-7} * 1 * I}{2 * 0.06}](https://tex.z-dn.net/?f=0.7%20%20%2A10%5E%7B-4%7D%3D%20%20%5Cfrac%7B%204%5Cpi%20%2A%2010%5E%7B-7%7D%20%20%2A%201%20%2A%20I%7D%7B2%20%2A%200.06%7D)
=> ![I = \frac{2 * 0.06 * 0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}](https://tex.z-dn.net/?f=I%20%20%3D%20%20%5Cfrac%7B2%20%2A%20%200.06%20%2A%20%200.7%20%2A10%5E%7B-4%7D%7D%7B%204%5Cpi%20%2A%2010%5E%7B-7%7D%20%2A%201%7D)
![I = 6.68 \ A](https://tex.z-dn.net/?f=I%20%20%3D%206.68%20%5C%20%20A)
Answer:
The acceleration of the train is 5 m/s².
Explanation:
Given:
let the initial velocity of a train = 5 m/s and
final velocity of a train = 45 m/s
time taken = 8 s
To find:
acceleration: ?
Solution:
We define acceleration as change in velocity per unit time that is the difference between the final velocity and initial velocity divided by time.
![Acceleration = \frac{\textrm{final velocity} - \textrm{initial velocity}}{time} \\](https://tex.z-dn.net/?f=Acceleration%20%3D%20%5Cfrac%7B%5Ctextrm%7Bfinal%20velocity%7D%20-%20%5Ctextrm%7Binitial%20velocity%7D%7D%7Btime%7D%20%5C%5C)
On substituting the above values we get the required acceleration
![Acceleration = \frac{45 - 5}{8}\\ =\frac{40}{8}\\ =5\ m/s^{2}](https://tex.z-dn.net/?f=Acceleration%20%3D%20%5Cfrac%7B45%20-%205%7D%7B8%7D%5C%5C%20%3D%5Cfrac%7B40%7D%7B8%7D%5C%5C%20%3D5%5C%20m%2Fs%5E%7B2%7D)
Therefore,the acceleration of the train is 5 m/s².
Answer:
You are a guest magician in a circus. One of your tricks is to place a football on an inclined plane without the football rolling over is explained below in details.
Explanation:
spinning ball halts after traveling some range due to friction energy act different direction of movement of the ball. you can observe in the figure.
Let any rolling ball of mass (m ) is traveling with velocity v ,
common effect on ball (N) = mg
because of motion, friction energy develops on the contact exterior and begins to resist the movement of the rolling ball.
hence,
fr = uN = umg act on communicating exterior, so, after any time due to friction energy rolling ball gets to rest.