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3 years ago

Suppose a logs mass is 5kg .after burning,the mass of the ash is 1kg .explain what may have happened to the other 4kg

1 answer:

5 0

The "missing" 4 kg may have escaped the scene of the fire in the
form of hot gases, and as particles of soot and ash that were seen
leaving in the form of "smoke".

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Are electrons lower in mass than neutrons

tamaranim1 [39]

Answer:

ya I just looked it up on Google

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3 years ago

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liq [111]

Answer:

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3 years ago

A car owner forgets to turn off the headlights of his car while it is parked in his garage. If the 12.0-V battery in his car is

luda_lava [24]

Answer:

It will take time=7.963 hours to completely discharge

Explanation:

The energy available in the battery is:

Energy stored=Power×Time

Energy stored=(ΔV)I×t

Energy stored=(12.0V×43.0A.h)

Energy stored=516 W.h

The two headlights together consume a total power of:

$P=2*32.4W\\P=64.8W$

So the time required to completely discharge is:

$time=\frac{Energy.stored}{P}\\ time=\frac{516 W.h}{64.8W}\\ time=7.963hours$

It will take time=7.963 hours to completely discharge

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4 years ago

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In a carnival booth, you can win a stuffed giraffe if you toss a quarter into a small dish. the dish is on a shelf above the poi

Georgia [21]

components of the speed of the coin is given as

$v_x = v cos60$

$v_x = 6.4 cos60 = 3.2 m/s$

$v_y = vsin60$

$v_y = 6.4 sin60 = 5.54 m/s$

now the time taken by the coin to reach the plate is given by

$t = \frac{\delta x}{v_x}$

$t = \frac{2.1}{3.2}$

$t = 0.656 s$

now in order to find the height

$h = vy * t + \frac{1}{2} at^2$

$h = 5.54 * 0.656 - \frac{1}{2}*9.8*(0.656)^2$

$h = 1.52 m$

so it is placed at 1.52 m height

3 0

3 years ago

What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)

Alenkasestr [34]

Answer:

So percentage error will be 2 %

Explanation:

We have given initial value of acceleration due to gravity $g=10m/sec^2$

And final value of acceleration due to gravity $g=9.8m/sec^2$

We have to find the percentage error

We know that percentage error is given by $percentage\ error=\frac{initial\ value-final\ value}{initial\ value}\times 100$

So $percentage\ error=\frac{10-9.8}{10}\times 100=2$ %

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3 years ago