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dybincka [34]
3 years ago
5

15℅ of $9 is $______________

Mathematics
2 answers:
Rasek [7]3 years ago
8 0
To do this we can write 15% as a decimal which will be 0.15. 0.15 times 9 will be  1.35 dollars.
stiv31 [10]3 years ago
6 0
The answer is 1.35 dollar
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Eight people audition for a choir. The choir director must choose one soprano, one altar and one soprano. In how many ways can t
Trava [24]
There are 72 different ways the director can fill the positions.

(1+2+3+4+5+6+7+8) x 2


You multiply it by 2 because there are going to be 4 other people who will not have a position, and 8/4 is 2.
4 0
4 years ago
Read 2 more answers
Can someone please help me
Oksana_A [137]
The answer is -31 over 12.
5 0
3 years ago
Read 2 more answers
Please help its very hard
allochka39001 [22]

This histogram is skewed to the left and its distribution's center would be three (3).

<h3>What is a histogram?</h3>

A histogram is used to graphically represent a set of data points into user-specified ranges, especially through the use of rectangular bars.

In this scenario, we can infer the following about the histogram distribution's center, spread, and overall shape:

  • This histogram is skewed to the left.
  • Its distribution's center would be three (3).
  • The spread implies that more students are between 58-59 and 60-61 inches.
  • The shape shows that many of the values are at the lower end.

Read more on histogram here: brainly.com/question/21304143

#SPJ1

8 0
2 years ago
Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).
Sergio [31]
Hello,

Equation is y=k(x-1)²-9
and when x=0,y=-6==>-6=k*1²-9==>k=3

y=3(x-1)²-9
when y=0, 3(x-1)²-9=0
==>(x-1-√3)(x-1+√3)=0
x-intercepts are (1+√3,0) and (1-√3,0)

Answer B.

3 0
4 years ago
From a club of 24 people, in how many ways can a group of four members be selected to attend a conference?
Kamila [148]

Answer:

255,024

Step-by-step explanation:

24 x 23 x 22 x 21

24 options for the first member

23 options for the second member

22 options for the third member

21 options for the last member

6 0
3 years ago
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