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3 years ago

14

URGENT: true or false: liquids can be poured from one container to another because there are no attraction forces between atoms

or molecules

2 answers:

sashaice [31]3 years ago

4 0

Answer:

False

Explanation:

It's common sense

never [62]3 years ago

4 0

Answer:

True

Explanation:

Water doesnot have any definite shape.
There is less attraction between particles .
Hence water can move one container to another

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a small rock with a mass 0.20 kg is attachted to the lower wns od a long string and moves in a horixontal circle with radiu 0.6

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A positron has a mass of 9.11 x 10^-31 kg, and charge qp = +e = +1.60 x 10^-19 C. It is moving towards an α particle (qα = +2e,

OlgaM077 [116]

Answer:

Part a)

$v = 2.25 \times 10^6 m/s$

Part b)

$r = 0.72 \times 10^{-10} m$

Explanation:

As we know that alpha particle remain at rest always so the energy of system of positron and alpha particle will remain constant

So we will have

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

here we know that

$q_1 = 1.6 \times 10^{-19} C$

$q_2 = 2(1.6 \times 10^{-19}) C$

also we have

$r_1 = 2.00 \times 10^{-10} m$

$r_2 = 1.00 \times 10^{-10} m$

$v_1 = 3.00 \times 10^6 m/s$

$m = 9.11 \times 10^{-31} kg$

now from above equation we have

$2.304 \times 10^{-18} + 4.0995\times 10^{-18} = 4.608 \times 10^{-18} + \frac{1}{2}(9.11 \times 10^{-31})v^2$

$v = 2.25 \times 10^6 m/s$

Part b)

Now when it come to rest then again by energy conservation we can say

$\frac{kq_1q_2}{r_1} + \frac{1}{2}mv_1^2 = \frac{kq_1q_2}{r_2} + \frac{1}{2}mv_2^2$

now here final speed will be zero

$2.304 \times 10^{-18} + 4.0995\times 10^{-18} = \frac{(9/times 10^9)(1.6\times 10^{-19})(2\times 1.6 \times 10^{-19})}{r_2}$

$r = 0.72 \times 10^{-10} m$

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Calcula el tiempo que tarda en llegar a la Tierra la luz del sol si viaja a 300.000 km/s sabiendo que la distancia del sol a la

Strike441 [17]

Calculate the time it takes for sunlight to reach Earth if it travels at 300,000 km / s, knowing that the distance from the sun to the earth is 150,000,000 km. Express it in minutes

Answer:

8.3min

Explanation:

Given parameters:

Speed of sunlight = 300000km/s

Distance of sun and earth = 150000000km

Unknown:

Time in minutes = ?

Solution:

To solve this problem;

Speed = $\frac{distance }{time}$

Time = $\frac{distance}{speed}$

Now insert the parameters and find the speed;

Time = $\frac{150000000}{300000}$ = 500s

Now;

60s makes 1 minute

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Determine the unbalanced force necessary to accelerate a 2.60 kg object at a rate of 14.0 m/s².

slega [8]

Answer:

Explanation:

F = ma

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leonid [27]

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