The answer is λ₂ = 6.48 cm or 6.52 cm.
The out-of-tune guitar may have a wavelength between "6.48 cm" and "6.52 cm."
fb = |f2 − f1|
f₁ = 343/0.064
= 5276Hz
f₂ = 5276.9 Hz ± 17 Hz
f₂ = 5293.9 Hz or 5259.9 Hz
Now, calculating the possible wavelengths:
λ = 343/ 5259.9 or 343/ 5293.9
λ₂ = 6.48 cm or 6.52 cm
<h3>Why is beat frequency important?</h3>
When two waves with almost identical frequencies traveling in the same direction collide at a certain location, beats are produced. The opposing beneficial and harmful disruption causes the sound to alternatively be loud and weak whenever two sound waves with different frequencies reach your ear. This is referred to as beating.
The entire value of the frequency difference between the two waves is the beat frequency.
The following formula yields the beat frequency:
fb = |f2 − f1|
Learn more about beat frequency here:
brainly.com/question/14705053
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Kepler's second law of planetary motion<span> describes the speed of a </span>planet<span> traveling in an elliptical orbit around the sun. It states that a line between the sun and the </span>planetsweeps equal areas in equal times. Thus, the speed of theplanet<span> increases as it nears the sun and decreases as it recedes from the sun.</span>
They will rise to the 2nd layer of the atmosphere where the temperature decreases by a lot and then they will blow up
(a) This is a freefall problem in disguise - when the ball returns to its original position, it will be going at the same speed but in the opposite direction. So the ball's final velocity is the negative of its initial velocity.
Recall that
We have 
, so that
(b) The speed of the ball at the start and at the end of the roll are the same 8 m/s, so the average speed is also 8 m/s.
(c) The ball's average velocity is 0. Average velocity is given by 
, and we know that .
(d) The position of the ball 
at time 
is given by
Take the starting position to be the origin, 
. Then after 6 seconds,
so the ball is 42 m away from where it started.
We're not asked to say in which direction it's moving at this point, but just out of curiosity we can determine that too:
Since the velocity is positive, the ball is still moving up the incline.
