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2 years ago

4/8 x 4/8 i dont care if you answer want to be fwen :)

Mathematics

2 answers:

lana66690 [7]2 years ago

8 0

Answer:

1/4

Step-by-step explanation:

4/8×4/8

16/64

Aleonysh [2.5K]2 years ago

7 0

Answer:

1/4

Step-by-step explanation:

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Gary and Jessica exercise for a total of 18 hours per week. Jessica exercises 2 less than 3 times the hours that Gary exercises.

horsena [70]

<h3>Answer: 5</h3>

Work Shown:

g = number of hours that Gary exercises

3g-2 = number of hours that Jessica exercises

(g) + (3g-2) = 18

4g-2 = 18

4g = 18+2

4g = 20

g = 20/4

g = 5

Gary exercises 5 hours per week.

3 0

1 year ago

What is 0.00000000472 estimated as the product of a single digit and a power of 10?

Vesnalui [34]

$0\underbrace{.000000004}_{9\to}72=4.72\cdot10^{-9}$

5 0

3 years ago

Read 2 more answers

If Log 4 (x) = 12, then log 2 (x / 4) is equal to A. 11 B. 48 C. -12 D. 22

klio [65]

C I guess sorry if I get you a low score

6 0

3 years ago

In this diagram, BAC~EDF. If the area of BAC=15 in2, what is the area of EDF? 4, 5.

lesya692 [45]

Answer:

9.6 square inches.

Step-by-step explanation:

We are given that ΔBAC is similar to ΔEDF, and that the area of ΔBAC is 15 inches. And we want to determine the area of ΔDEF.

First, find the scale factor k from ΔBAC to ΔDEF:

$\displaystyle 5 k = 4$

Solve for the scale factor k:

$\displaystyle k = \frac{4}{5}$

Recall that to scale areas, we square the scale factor.

In other words, since the scale factor for sides from ΔBAC to ΔDEF is 4/5, the scale factor for its area will be (4/5)² or 16/25.

Hence, the area of ΔEDF is:

$\displaystyle \Delta EDF = \frac{16}{25}\left(15\right) = 9.6\text{ in}^2$

In conclusion, the area of ΔEDF is 9.6 square inches.

5 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

4/8 x 4/8 i dont care if you answer want to be fwen :)​

4/8 x 4/8 i dont care if you answer want to be fwen :)