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kicyunya [14]
2 years ago
13

PLEASE ANSWER I WILL MARK THE BRAINIEST ANSWER :)factorise: X^2 + 10x + 16

Mathematics
1 answer:
Damm [24]2 years ago
3 0

Answer:

(x+2)(x+8)

Step-by-step explanation:

1.)find factors of the third expression(16)that will add up to give the second expression(10)

16=2×8. 10=2+8

2.)substitute those factors inplace of 10

{x}^{2}  + 10x + 16

x {}^{2}  + 2x + 8x + 16

3.)factorise using grouping method

( {x}^{2}  + 2x) + (8x + 16)

x(x + 2) + 8(x + 2)

= (x + 2)(x + 8)

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A pair of jeans are originally priced at $30.00 jeans go on sale for 20% off, what is
Zigmanuir [339]

Answer:

The answer is 6

Step-by-step explanation:

5 0
3 years ago
A candy bar box is in the shape of a triangular prism the volume of the box is 2400 cubic centimeters part A: what is the height
Whitepunk [10]
The volume of a triangular prism is the "area of a triangle" times the "thickness."
The area of a triangle is (base times height) over 2.
V = ((b*h)/2)*T
Given V = 2400 cu. cm, b = 16 cm, T = 20 cm, and h is unknown,
h = (2V)/(bL) = (2*2400)/(16*20) = 15 cm

Note that the given 17 cm in the picture is useless.
3 0
3 years ago
What is 60/ 480 ? without calculator
romanna [79]

Answer:

1/8

Step-by-step explanation:

You must divide by common multipliers. so you can first divide the numerator and denominator by 10, which would make it 6/48, and then do that again with 6. Which then would give you the answer of 1/8.

4 0
3 years ago
What is the solution to this system of linear equations?
svetoff [14.1K]
It’s B
If y-x=6
Y +X =_10
then y= 6 + x, instead of y insert this no
6+ x+ x =-10
6 + 2x =-10 then collect like terms
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7 0
3 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
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