All categories

3 years ago

Which of the following best describes colloids?

Chemistry

2 answers:

Art [367]3 years ago

6 0

Answer: it's definitely b since its the one that makes the most sense plus i look it it up and im certain it is B

Sidana [21]3 years ago

5 0

Answer B, because clear ,pure substances makes more sense then others, i searched it all up and came up b, please give brainliest!! good luck

You might be interested in

The element iridium exists in nature as two isotopes: 191Ir has a mass of 190.9606 u, and 193Ir has a mass of 192.9629 u. The av

nlexa [21]

Answer: The percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope be 'x'. So, fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope will be '1 - x'

For $_{77}^{191}\textrm{Ir}$ isotope:

Mass of $_{77}^{191}\textrm{Ir}$ isotope = 190.9606 amu

Fractional abundance of $_{77}^{191}\textrm{Ir}$ isotope = x

For $_{77}^{193}\textrm{Ir}$ isotope:

Mass of $_{77}^{193}\textrm{Ir}$ isotope = 192.9629 amu

Fractional abundance of $_{77}^{193}\textrm{Ir}$ isotope = 1 - x

Average atomic mass of iridium = 192.22 amu

Putting values in equation 1, we get:

$192.22=[(190.9606\times x)+(192.9629\times (1-x))]\\\\x=0.3710$

Percentage abundance of $_{77}^{191}\textrm{Ir}$ isotope = $0.3710\times 100=37.10\%$

Percentage abundance of $_{77}^{193}\textrm{Ir}$ isotope = $(1-0.3710)=0.6290\times 100=62.90\%$

Hence, the percentage abundance of $_{77}^{191}\textrm{Ir}$ and $_{77}^{193}\textrm{Ir}$ isotopes are 37.10% and 62.90% respectively.

8 0

3 years ago

Which of the following is TRUE?Which of the following is TRUE?A basic solution does not contain H3O+An neutral solution does not

schepotkina [342]

Answer:

Explanation:

5 0

4 years ago

Calculate the molar solubility of ca(io3)2 in each solution below. the ksp of calcium iodate is7.1 × 10−7.

e-lub [12.9K]

In order to find the answer, use an ICE chart:

Ca(IO3)2...Ca2+......IO3-
some.......0..........0 
less.......+x......+2x 
less........x.........2x

Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³

K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
x = molar solubility = 5.6 x 10⁻³ M

The answer is 5.6 x 10 ^ 3 M. (molar solubility)

5 0

3 years ago

Read 2 more answers

- Cd SO₃ What is the name for this ionic compound?

Oxana [17]

Answer:

cadium (II) sulfite

Explanation:

Cd is cadium

S is sulfur

03 is 3 oxygen

8 0