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hjlf
3 years ago
13

Under what conditions of temperature and pressure do real gases behave most like ideal gases?

Chemistry
1 answer:
bekas [8.4K]3 years ago
4 0

Answer:

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them

Explanation:

answer right in there:)

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A nonplar solvent would most easily dissolve which of the following substances?
Alika [10]

Answer:

Nonpolar Solvent. Carbon tetrachloride. CCl4

Explanation:

The other compounds listed are polar;

polar substances are by their nature more soluble in Other polar compounds. NH3 is a gas; so unless it was a very specific compound you needed in ammonia gas, it, being also polar as well as a gas would not be a good choice for this question.

7 0
3 years ago
At 1000 K, a sample of pure NO2 gas decomposes. 2 NO2(g) equilibrium reaction arrow 2 NO(g) + O2(g) The equilibrium constant KP
kirill115 [55]

<u>Answer:</u> The pressure of NO and NO_2 in the mixture is 0.58 atm and 0.024 atm respectively.

<u>Explanation:</u>

We are given:

Equilibrium partial pressure of O_2 = 0.29 atm

For the given chemical equation:

                   2NO_2(g)\rightleftharpoons 2NO(g)+O_2(g)

Initial:              a

At eqllm:        a-2x          2x          x

Calculating for the value of 'x'

\Rightarrow x=0.29

Equilibrium partial pressure of NO = 2x = 2(0.29) = 0.58 atm

Equilibrium partial pressure of NO_2 = a - 2x = a - 2(0.29) = a - 0.58

The expression of K_p for above equation follows:

K_p=\frac{p_{O_2}\times (p_{NO})^2}{(p_{NO_2})^2}

We are given:

K_p=158

Putting values in above expression, we get:

158=\frac{0.29\times (0.58)^2}{(a-0.58)^2}\\\\a=0.555,0.604

Neglecting the value of a = 0.555 because it cannot be less than the equilibrium concentration.

So, a=0.604

Equilibrium partial pressure of NO_2 = (a - 0.58) = (0.604 - 0.58) = 0.024 atm

Hence, the pressure of NO and NO_2 in the mixture is 0.58 atm and 0.024 atm respectively.

4 0
3 years ago
Which symbol depicts an oxidizing reagent
qaws [65]

That is the symbol that depicts an oxidizing reagent

3 0
1 year ago
0.0000250 m in scientific notation
malfutka [58]
2.50 × 10 ^-5. Move your decimal until you get a whole number. Then count how many times you moved it and that is your exponent. So your exponent is -5 because you're going to the left, if you're going to the right it would be a positive number. 
3 0
3 years ago
All of the following are properties of molecular compounds except
icang [17]

Answer: the answer is c.

Explanation:

i juss guessed and it was right?

5 0
3 years ago
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