Answer:
Theanswer to your question is:
Limiting reactant = FeCl₃
Excess reactant = 1.66 g of Mg
Explanation:
Data
Mg = 41 g = 24.31 g/mol
FeCl₃ = 175 g = 162.2 g/mol
3Mg(s) + 2FeCl₃(s) → 3MgCl₂(s) + 2Fe(s)
3(24.31) of Mg ------------------ 2(162.2) of FeCl₃
72.93 g of Mg ------------------ 324.4 g of FeCl₃
Theoretical Proportion = 324.4/72.93 = 4.44
Practical proportion = 175 / 41 = 4.2
As the proportion disminishes the limiting reactant is FeCl₃.
Excess reactant
72.93 g of Mg ------------------ 324.4 g of FeCl₃
x ------------------------- 175 g of FeCl₃
x = (175 x 72.93) / 324.4
x = 39.34 g of Mg
Excess = 41 - 39.34
= 1.66 g of Mg
Answer:
3.0 moles.
Explanation:
- It is a stichiometry problem.
- The chemical reaction of reacting hydrogen with oxygen to produce water is:
<em>H₂ + 1/2 O₂ → H₂O.</em>
- It is clear that <em><u>1.0 mole of H₂</u></em> reacts with 0.5 mole of O₂ to produce <u><em>1.0 mole of water</em></u>.
- The ratio of the reacting hydrogen to the produced water is 1:1.
∴ The number of moles of water created from reacting 3.0 moles of hydrogen completely with excess oxygen = 3.0 moles.
Radioactive decay or disintegration is a process through which unstable nuclei form q more stable nuclei by the release of elementary particles like alpha particles, beta, protons, neutrons etc along with the release of energy.
In the given examples:
a) N-13 will get converted in to carbon, C-12 along with the release of a proton as shown below:
₇N¹³ → ₆C¹² + ₁H¹
b) N-15 will get converted in to boron B-11 along with the release of an alpha particle
₇N¹⁵ → ₅B¹¹ + ₂He⁴
