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Anton [14]
3 years ago
10

I NEED THE RIGHT ANSWER ASAP NO LINKS !!! This is a Science question

Physics
1 answer:
mylen [45]3 years ago
8 0

Answer:

12+7 and 12+7and 12-7AND -12+7

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What happens when an object is moved against gravity, such as rolling a toy car up a ramp?
BlackZzzverrR [31]

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

3 0
3 years ago
Taking test, need physics help<br> ASAP please!
Neko [114]

Answer:

one free advice don't believe all this free advices give din brainly ok

5 0
3 years ago
A golfer strikes her tee shot with the following velocities, vx = 106 m/s &amp; vy = 66.2 m/s. a. What is the velocity of flight
lara [203]

Answer:

a) V ≈ 125 m/s;  b) Δt = 13.24 s;  c) ΔS ≈ 1450 m

Explanation:

a) We have just to calculate the vector resultant.

V² = 106² + 66.2²

V² = 15618.44

V ≈ 125 m/s

b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.

In vertical:

V = V₀ + a * t

V = 66.2 - g * t

0 = 66.2 - 9.8 * t

t ≈ 6.76 s

So: Δt = 13.24 s

c) In horizontal:

V = ΔS / Δt

106 = ΔS / 13.52  ⇒  ΔS = 106 * 13.52

ΔS = 106 * 13.52

ΔS = 1433,12

ΔS ≈ 1450 m

3 0
1 year ago
Which of the following expenses will most likely be the most expensive?
Jlenok [28]
Option B makes the most sense. Option A is something you acquire, it wouldn't really cost anything. Utilities usually do not cost more than housing. Savings are subjective, dependent on the person. So option B.
Hope it helps!
4 0
3 years ago
A person jumps out a fourth-story window 14 m above a firefighter safety net. The survivor stretches the net 1.8 m before coming
Monica [59]

Answer:

The deceleration is  a =  - 76.27 m/s^2

Explanation:

From the question we are told that

   The height above  firefighter safety net is H  = 14 \ m

   The length by which the net is stretched is s =  1.8 \ m

   

From the law of energy conservation

    KE_T + PE_T =  KE_B + PE_B

 Where KE_T is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

   and  PE_T is the potential energy of the before jumping  which is mathematically represented at

          PE_T  = mg H

and  KE_B is the kinetic energy of the person just before landing on the safety net  which is mathematically represented at

        KE_B = \frac{1}{2} m v^2

and  PE_B is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

   So the above equation becomes

          mgH =  \frac{1}{2} m v^2

=>           v =  \sqrt{2 gH }

    substituting values

                v =  16.57 m/s

Applying the equation o motion

             v_f =  v  + 2 a s

Now the final velocity is zero because the person comes to rest

      So

         0 = 16.57 + 2 * a * 1.8

            a =  - \frac{16.57^2 }{2 * 1.8}

            a =  - 76.27 m/s^2

         

         

4 0
3 years ago
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