Why cable color codes are important ? what if we use three phase cables without color

Physics

1 answer:

Degger [83]3 years ago

4 0

Answer:

Cable color codes are very important for example, If something is not wired properly, it can result in injuries, deaths, fires, and many other problems. This is why there are well-established wire color codes to ensure those working with an around this type of equipment can ensure everything is wired safely and effectively. If we used three phase cables without color code, this can lead too incorrect things that might be a hazard too get not fix and learning new color codes would be hard therefore we should stick too the same color codes for cables and it saves the hassle for needing too check every cable cord color then the original one signed too it.

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A spring with a spring constant kk of 100 pounds per foot is loaded with 1-pound weight and brought to equilibrium. it is then s

tino4ka555 [31]

Given:

k = 100 lb/ft, m = 1 lb / (32.2 ft/s) = 0.03106 slugs

Solution:

F = -kx
mx" = -kx
x" + (k/m)x = 0

characteristic equation:
r^2 + k/m = 0
r = i*sqrt(k/m)

x = Asin(sqrt(k/m)t) + Bcos(sqrt(k/m)t)

ω = sqrt(k/m)
2π/T = sqrt(k/m)
T = 2π*sqrt(m/k)
T = 2π*sqrt(0.03106 slugs / 100 lb/ft)
T = 0.1107 s (period)

x(0) = 1/12 ft = 0.08333 ft
x'(0) = 0

1/12 = Asin(0) + Bcos(0)
B = 1/12 = 0.08333 ft

x' = Aω*cos(ωt) - Bω*sin(ωt)
0 = Aω*cos(0) - (1/12)ω*sin(0)
0 = Aω
A = 0

So B would be the amplitude. Therefore, the equation of motion would be x = 0.08333*cos[(2π/0.1107)t]

5 0

4 years ago

When 15 newtons of force is applied to the 0.5 kg book, the friction keeps the book from sliding down the wall. What is the mini

valkas [14]

Answer:

15 N and 3.061

Explanation:

From the question,

The minimum force of friction to keep the book from sliding = 15 N.

using

F = mgμ................. Equation 1

Where F = Frictional Force, m = mass of the book, g = acceleration due to gravity, μ = coefficient of friction.

make μ the subject of the equation

μ = F/mg............... Equation 2

Given: F = 15 N, m = 0.5 kg, g = 9.8 m/s²

Substitute into equation 2

μ = 15(0.5×9.8)

μ = 15/4.9

μ = 3.061

Hence the coefficient of friction to keep the book from sliding = 3.061

4 0

4 years ago

Read 2 more answers

One student is studying three rock samples, Rock 1, Rock 2, and Rock 3. The characteristics of the three rocks are listed below.

melamori03 [73]

To answer this question, we will refer to the attached diagram which represents the complete rock cycle.

Rock 1:
Formed when rock 2 and rock 3 were subjected to intense heat and pressure inside the earth.
Referring to the diagram, we will find that heat and pressure are the factors required to form metamorphic rocks
Therefore, rock 1 is metamorphic

Rock 2:
Formed when rock 1 and rock 3 were broken down into mineral (sediments) which accumulate and are subjected to pressure.
Referring to the diagram, we will find that this description would lead to the formation of sedimentary rocks.
Therefore, rock 2 is a sedimentary rock.

Rock 3:
Formed when rock 1 and rock 2 were buried inside the earth and melted because of heat and magma.
Referring to the diagram, we would find that melting then cooling of magma would lead to formation of igneous rock.
Therefore, rock 3 is igneous rock.

Based on the above, the correct choice would be:
Rock 1: Metamorphic
Rock 2: Sedimentary
Rock 3: Igneous