Coulombs law says that the force between any two charges depends on the amount of charges and distance between them. This force is directly proportional to the magnitude of the two charges and inversely proportional to the distance between them.
![F=k\frac{|q_1| |q_2|}{r^2}](https://tex.z-dn.net/?f=F%3Dk%5Cfrac%7B%7Cq_1%7C%20%7Cq_2%7C%7D%7Br%5E2%7D)
where
are charges,
is the distance between them and k is the coulomb constant.
case 1:
![q_1=-e\\ q_2=+3e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||3e|}{(100pm)^2}=3ke^2\times10^8](https://tex.z-dn.net/?f=q_1%3D-e%5C%5C%20q_2%3D%2B3e%5C%5C%20r%3D100pm%5C%5C%20%5CRightarrow%20F%3Dk%5Cfrac%7B%7C-e%7C%7C3e%7C%7D%7B%28100pm%29%5E2%7D%3D3ke%5E2%5Ctimes10%5E8)
case 2
![q_1=-e\\ q_2=+2e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||2e|}{(100pm)^2}=2ke^2\times10^8](https://tex.z-dn.net/?f=q_1%3D-e%5C%5C%20q_2%3D%2B2e%5C%5C%20r%3D100pm%5C%5C%20%5CRightarrow%20F%3Dk%5Cfrac%7B%7C-e%7C%7C2e%7C%7D%7B%28100pm%29%5E2%7D%3D2ke%5E2%5Ctimes10%5E8)
case 3:
![q_1=-e\\ q_2=+e\\ r=100pm\\ \Rightarrow F=k\frac{|-e||e|}{(200pm)^2}=0.25ke^2\times10^8](https://tex.z-dn.net/?f=q_1%3D-e%5C%5C%20q_2%3D%2Be%5C%5C%20r%3D100pm%5C%5C%20%5CRightarrow%20F%3Dk%5Cfrac%7B%7C-e%7C%7Ce%7C%7D%7B%28200pm%29%5E2%7D%3D0.25ke%5E2%5Ctimes10%5E8)
Comparing the 3 cases:
The maximum potential force according to coulombs law is between -1 charge and +3 charge separated by a distance of 100 pm.
Well idk if this helps but the formula to solve acceleration is
a=F/m=(100kg)=1.0m/s 2
![\huge\mathsf{\red{\underline{\underline{Answer}}}}](https://tex.z-dn.net/?f=%5Chuge%5Cmathsf%7B%5Cred%7B%5Cunderline%7B%5Cunderline%7BAnswer%7D%7D%7D%7D)
When an opaque obstacle is placed between a source of light and a screen, a shadow of the obstacle is formed on the screen. The kind of shadow depends on the size of the source of light. In other words, the earth casts its shadow on the moon. The solar eclipse occurs when the moon comes between the sun and the earth.
Water that flows across the surface is called a;
Runoff
That's when rain has saturated the ground to the point it cant hold anymore and it runs over the surface.