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3 years ago

Calculate each of the following quantities. (a) mass in kilograms of 3.7 x 1020 molecules of NO2

Chemistry

1 answer:

HACTEHA [7]3 years ago

7 0

Answer:

The answer to your question is: 0.028 kg of NO2

Explanation:

Data

3.7 x 10²⁰ molecules of NO2 in kg

MW of NO2 = 14 + (16 x 2) = 14 + 32 = 46 kg

1 mol of NO2 --------------------- 6.023 x 10 ²³ molecules

x --------------------- 3.7 x 10²⁰ molecules

x = 3.7 x 10²⁰ x 1 / 6.023 x 10 ²³

x = 0.00061 mol

1 mol of NO2 --------------------- 46 kg of NO2

0.00061 mol ------------------ x

x = 0.00061 x 46/1

x = 0.028 kg of NO2

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choli [55]

Answer:

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Explanation:

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3 years ago

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irga5000 [103]

Explanation:

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In both the formulas, the nature of atoms remains the same but the number differs.

For Example: The molecular formula of oxalic acid is $C_2H_2H_4$ but the empirical formula of oxalic acid is $CHO_2$

To calculate the molecular formula, we need to find the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

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3 years ago

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2 years ago

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Answer:

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3 years ago

Calculate the volume of compound Y needed to make a 350 pg/ml treatment solution in 2 ml of 1x PBS using a stock solution contai

harina [27]

Answer:

14 mL

Explanation:

To prepare a solution by a concentrated solution, we must use the equation:

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The final solution must have 2 mL and a concentration of 350 pg/mL, and the initial solution has a concentration of 50 pg/mL.

Then:

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3 years ago