A liquid is boiled in a beaker until all of the liquid has evaporated. a powdery substance remains in the beaker. which does thi
2 answers:
You might be interested in
Answer : The correct option is, (B) 0.11 M
Solution :
First we have to calculate the concentration and
.
The given equilibrium reaction is,
Initially 0.70 0.70 0
At equilibrium (0.70-x) (0.70-x) x
The expression of will be,
Now put all the given values in the above expression, we get:
By solving the term x, we get
From the values of 'x' we conclude that, x = 0.83 can not more than initial concentration. So, the value of 'x' which is equal to 0.83 is not consider.
Thus, the concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = (0.70-x) = (0.70-0.59) = 0.11 M
The concentration of at equilibrium = x = 0.59 M
Therefore, the concentration of at equilibrium is 0.11 M
Answer:
V = 34.55 L
Explanation:
Given that,
No of moles, n = 1.4
Temperature, T = 20°C = 20 + 273 = 293 K
Pressure, P = 0.974 atm
We need to find the volume of the gas. It can be calculated using Ideal gas equation which is :
PV=nRT
R is gas constant,
Finding for V,
So, the volume of the gas is 34.55 L.