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topjm [15]
3 years ago
8

Suppose of hcl and of o2 are added to an empty flask. How much will be in the flask at equilibrium?A. None. B. Some, but less th

an 155. mmol, C. 155. mmol, D. More than 155. mmol
Chemistry
1 answer:
serg [7]3 years ago
7 0

This is an incomplete question, here is a complete question.

Hydrogen chloride and oxygen react to form water and chlorine, like this:

4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)

Use this chemical equation to answer the questions in the table below.

Suppose 155. mmol of HCl and 38.8 mmol of O₂ are added to an empty flask. How much HCl will be in the flask at equilibrium?

(1) None.

(2) Some, but less than 155. mmol,

(3) 155. mmol,

(4) More than 155. mmol,

Answer : The correct option is, (1) None

Explanation :

The given balanced chemical reaction is:

4HCI(g)+O_2(g)\rightarrow 2H_2(g)+2CI_2(g)

From the balanced chemical reaction, we conclude that

As, 4 mmole of HCl react with 1 mmoles of O_2

So, 155. mmole of HCl react with \frac{155.}{4}\times 1=38.75 mmoles of O_2

That means, O_2 is excess reagent and HCl is a limiting reagent. All the moles of HCl will consume.

Hence, the correct option is, None.

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How many moles of Mg(OH)2 will react with 2.5 mol HCI?
bekas [8.4K]

Answer:

1.25mole of Mg(OH)₂

Explanation:

The reaction is between Mg(OH)₂ and HCl, this is a neutralization reaction between an acid and a base.

         Mg(OH)₂   +   2HCl   →   MgCl₂   + 2H₂O

The balanced reaction equation is given above.

           2 mole of HCl reacts with 1 mole of Mg(OH)₂

So,       2.5mole of HCl will react with \frac{2.5}{2}  = 1.25mole of Mg(OH)₂

The number of moles of Mg(OH)₂ is given as 1.25mol

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