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2 years ago

What is the area of the trapezoid?

Mathematics

1 answer:

Ulleksa [173]2 years ago

6 0

the area is 160 cm^2

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Mama L [17]

Hole? It depends how big it is. Since there is no hole being depicted in this question, the answer is inexcusably 2ft

7 0

3 years ago

What is the vertex of the absolute value function defined by ƒ(x) = |x + 5| + 7?

Mandarinka [93]

<span>hello :
اthe vertex of the absolute value function defined by ƒ(x) = |x + 5| + 7 is :
</span>(-5,7) because when : x= - 5 ...f(-5) = |- 5 + 5| + 7 = 0+ 7 = 7

7 0

2 years ago

Read 2 more answers

9. Plot the points A (-2,3), B(2,-3), C(2,3) ,D(-2,3) join the points and find the distance between each point.

pav-90 [236]

Answer:

AB=7.21 unit

BC=6 unit

CD=7.21 unit

AD= 6 unit

AC=4 unit

BD=4 unit

Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula : $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}$

AB=7.21 unit

$B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}$

BC=6

$C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}$

CD=7.21

$A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}$

AD=6

$A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)$

$AC=\sqrt{(2+2)^2+(3-3)^2}$

AC=4

$B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)$

BD= $\sqrt{(-2-2)^2+(-3+3)^2}$

BD=4

4 0

2 years ago

Tanya ran 400 meters on Tuesday and 800 on Wednesday. If she ran 16,256 meters in all, how many did she run on Thursday? Show wo

loris [4]

Here's what I got. Hope that helps!

5 0

3 years ago

Read 2 more answers

How to found the volume

never [62]

The formula to find the volume is 1/2(l*w*h)
Height= 7.6
Width=9
Length=13
So, 1/2(7.6*9*13) and you will get the answer

7 0

2 years ago