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Tju [1.3M]
3 years ago
8

Read the list of

Chemistry
2 answers:
Ksenya-84 [330]3 years ago
6 0
Answer
B I’m pretty sure
Explanation
Paladinen [302]3 years ago
3 0
Orange juice and tougher
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Why do elements that have positive ions occur on the left side of the periodic table?
HACTEHA [7]
The elements on the left side of the periodic table are positive ions because they all lose electrons to find balance, thus leaving them with a positive charge.
4 0
3 years ago
Round to 4 significant figures.<br> 35.5450
Masja [62]

Answer:

35.5450 will be rounded to 35.55

Explanation:

=35.5450

if the last digit is less than 5 then it will be ignored

=35.545

when the dropping digit is 5 then the retaining digit will increse by a factor of 1

=35.55

i hope this will help you

3 0
3 years ago
Read 2 more answers
The mass of a single gold atom is 3.27X10^-22 grams. How many gold Adams with there be in 57.8 mg of gold.
vichka [17]

Answer:

18 * 10^19 atoms

Explanation:

We must first convert 57.8 mg to grams.

If 1000 mg = 1g

  57.8 mg = 57.8/1000 = 57.8 * 10^-3 g

Now;

If 1 gold atom has a mass of 3.27X10^-22 grams

x gold atoms have a mass of 57.8 * 10^-3 g

x = 57.8 * 10^-3 g/3.27X10^-22 g

x = 18 * 10^19 atoms

7 0
3 years ago
In acidic aqueous solution, the purple complex ion Co(NH3)5Br2+ undergoes a slow reaction in which the bromide ion is replaced b
kirill115 [55]

Answer:

A) 0.065 M is its molarity after a reaction time of 19.0 hour.

B) In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

Explanation:

Co(NH_3)_5(H_2O)_3+[Co(NH_3)5Br]^{2+}(Purple)(aq)+H_2O(l)\rightarrow [Co(NH_3)_5(H_2O)]^{3+}(Pinkish-orange)(aq)+Br^-(aq)

The reaction is first order in [Co(NH_3)5Br]^{2+}:

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=0.100 M

a) Final concentration of [Co(NH_3)5Br]^{2+} after 19.0 hours= [A]

t = 19.0 hour = 19.0 × 3600 seconds ( 1 hour = 3600 seconds)

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

[A]=0.100 M\times e^{-6.3\times 10^{-6} s^{-1}\times 19.0\times 3600 s}

[A]=0.065 M

0.065 M is its molarity after a reaction time of 19.0 h.

b)

Initial concentration of [Co(NH_3)5Br]^{2+}= [A_o]=x

Final concentration of [Co(NH_3)5Br]^{2+} after t = [A]=(100\%-69\%) x=31\%x=0.31x

Rate constant of the reaction = k = 6.3\times 10^{-6} s^{-1}

The integrated law of first order kinetic is given as:

[A]=[A_o]\times e^{-kt}

0.31x=x\times e^{-6.3\times 10^{-6} s^{-1}\t}

t = 185,902.06 s = \frac{185,902.06 }{3600} hour = 51.64 hours ≈ 52 hours

In 52 hours [Co(NH_3)5Br]^{2+} will react 69% of its initial concentration.

6 0
3 years ago
What happens when stress builds at faults? Select three options
Stels [109]

Answer:

When Stress builds up at faults, the 3 options that are correct and can happen

- Rock can bend and break;

- Earthquakes develop at Earth's surface

- Forces affect Earth's rocks

Explanation:

This is a Geography question

- Rock can bend and break

When Stress builds up at faults, it leads to a geologic activity that causes a lot of pressure that lead to the movement of the earth's crust. The movement creates such intense pressure on the rocks, that, with time, they twist, bend, and break due to this pressure.

- Earthquakes develop at Earth's surface

As explained earlier, this intense pressure can lead to rocks breaking, as these rocks break inside the earth's crust, the gaps that come into play after the breaking of the rocks causes the remaining rocks to adjust, releasing a lot of force, and subsequently creating earthquakes.

- Forces affect Earth's rocks

As explained earlier, the forces resulting from these intense pressures, affect the earth's rocks. They move them both vertically and horizontally, change their shape and eventually break them.

Hope this Helps!!!

8 0
3 years ago
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