Sea level because air a much thinner at higher altitudes
When a change in PH = 10^-ΔPH
so the change = 10^-3.2
change depends on two factor 0.00063 (10^-3.2)and factor 1585 (10^3.2)depending on the way which the change goes.if PH change from PH=0 to PH= 3.2 so the change is decreasing from concentration from 1 mol to 0.00063 and if PH change from PH = 3.2 to PH=0 so the change is increasing by a factor of 1585.
Answer:
The mass percent of aluminum sulfate in the sample is 16.18%.
Explanation:
Mass of the sample = 1.45 g
Mass of the precipitate = 0.107 g
Moles of aluminum hydroxide = 
According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .
Then 0.001372 moles of aluminum hydroxide will be obtained from:
Mass of 0.000686 moles of aluminum sulfate :
= 0.000686 mol × 342 g/mol = 0.2346 g
The mass percent of aluminum sulfate in the sample:
A student measures the volume of a solution to be 0.01370 have 5 significant digits in this measurement.
<h3>What are significant digits?</h3>
The significant digits are the minimum number from zero to nine for reporting any measurement where the digits are uncertain.
The significant digits starting from zero are not significant digits, decimal is not a significant digit, and ending zero after the decimal are significant digits.
Therefore, the student measures the volume of a solution to be 0.01370 5 significant digits are in this measurement.
Learn more about significant digits, here:
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