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Illusion [34]
3 years ago
15

Which statement best explains the genetic variation that results from sexual

Chemistry
2 answers:
Mkey [24]3 years ago
7 0

Answer:

Each chromosome contains many copies of the same gene

Lubov Fominskaja [6]3 years ago
6 0

Answer:

Offspring receive a mix of genes from two different parents

Good luck!

You might be interested in
A ________ can be defined as a very large molecule constructed from repeated molecular fragments or segments.
Semenov [28]
The Answer is D. a polymer is a substance that has a molecular structure consisting of a large number of similar units bonded together
7 0
3 years ago
100 billion in scientific notation?
bulgar [2K]

Answer: 1×10^11

Explanation:

<u>concept to know:</u> scientific notation must be written in the form of a × 10^b

where 0<a<10.

100 billion= 100,000,000,000

there are 11 zeros after 1

1 × 10^11

Hope this helps!! :)

3 0
4 years ago
Read 2 more answers
Write and balance a complete chemical reaction equation for the combustion of butane. Butane has carbon atoms. Butane has hydrog
Lilit [14]

Answer:

The balanced reaction is this:

2 C₄H₁₀ (g)  +  13 O₂(g) →  8 CO₂(g) +  10 H₂O (g)

Explanation:

Combustion is a chemical reaction whose reagents are oxygen, usually in excess and a hydrocarbon to generate carbon dioxide and water in the form of steam, as products.

Butane is considered as a reactant and it is a sort of alkane, in this case with 4 C (prefix but).

O₂ is needed for the complete combustion of butane.

5 0
3 years ago
Answer all parts of the following questions on Particle Stoichiometry.
Sever21 [200]
1. Translate, predict the products, and balance the equation above. 

Li + Cu(NO3)2 = Li(NO3)2 + Cu

2. How many particles of lithium are needed to produce 125 g of copper? 

125 g Cu ( 1 mol / 63.55 g ) (1 mol Li / 1 mol Cu ) ( 6.022 x 10^23 particles / 1 mol ) = 1.18x10^24 Li particles

3. How many grams of lithium nitrate are produced from 4.83E24 particles of copper (II) nitrate?

4.83E24 particles of copper (II) nitrate ( 1 mol / 6.022x10^23 particles ) (1 mol Li(NO3)2 / 1 mol Cu(NO3)2 ) ( 130.95 g / 1 mol ) = <span>1043.77 grams Li(NO3)2</span>
3 0
3 years ago
A solution is 0.10 M in Pb(NO3)2 and 0.10 M in AgNO3. Solid NaI is added until the second solid compound is on the verge of prec
nekit [7.7K]

Answer:

The compound which will precipitate first will be AgI with 2.9X10^{-4}

Explanation:

In order to precipitate a salt solution the ionic product of salt must exceed the solubility product.

Given:

Ksp of AgI = 1.5X10^{-16}

Ksp of PbI2= 1.5X10^{-9}

As Ksp of AgI is very low it will precipitate faster than lead iodide.

Now, higher the concentration of AgI solution taken faster its precipitation.

In the given choice the highest concentration solution of AgI is 2.9X10^{-4}

4 0
3 years ago
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