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Elina [12.6K]
3 years ago
5

if the bar and block are too heavy, one of the strings may break. assuming that the two strings are identical, which one will br

eak first?
Physics
1 answer:
DerKrebs [107]3 years ago
7 0

The string that will break first depends on the weight of the block or bar subjected to such string.

According to Hook's law, the force applied to an elastic material is directly proportional to the extension of the material.

F= kx

where;

  • <em>F is the force applied to the object = weight of the object</em>

For given two identical strings, the string that will break first depends on the mass of the bar and the block.

  • If the bar is heavier than the block, then the string subjected to the bar will break first.
  • On the other hand, if the block is heavier than the bar, then the string subjected to the block will break first.

Thus, the string that will break first depends on the weight of the block or bar subjected to such string.

Learn more here:brainly.com/question/4404276

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Which equation would you use to solve the following problem?
aivan3 [116]

The correct answer to the question is : C)The problem is asking to solve for work; W = F × d

EXPLANATION:

As per the question, the distance covered by the object d = 29 m.

The force that acts on the object is F = 289 N.

We are asked to choose the correct equation for work done.

Work is said to be done on a body or by a body if the applied force has a component along the direction of displacement.

Mathematically work done W = force × displacement

                                                  = F × d

As per the question, we are given distance covered and applied force.

Hence, the correct equation for calculating work done by the object is equation C.


6 0
3 years ago
Read 2 more answers
In the diagram, q1 = +1.39*10^-9 C and q2 = +3.22*10^-9 C. The electric field at point P is zero. What is the distance from P to
Sphinxa [80]

Answer:

0.388

Explanation:

6 0
4 years ago
A 36N force applied vertically upwards on an object causes it to accelerate at 2.0m/s2. What is the object's mass?
Natalija [7]

Force  =  mass  * acceleration

mass = Force/acceleration

        = 36/2

mass = 18 kg

7 0
3 years ago
A bolt is to be tightened with a torque of 7.0 N · m. If you have a wrench that is 0.55 m long, what is the least amount of forc
kodGreya [7K]

To solve this problem we will apply the given concept for torque which explains the relationship between the force applied and the distance to a given point. Mathematically this relationship is given as

\tau = F*d \rightarrow F = \frac{\tau}{d}

Where,

\tau = Torque

F = Force

d = Distance

Our values are given as,

\tau = 7.0Nm , d = 0.55m

Therefore replacing we have that the force is

F = \frac{7}{0.55}

F = 12.72N

Therefore the least amount of force that you must exert is 12.72N

4 0
3 years ago
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of ma
tresset_1 [31]

Answer:

Explanation:

a. Given that:

m- mass of first & second piece, 3m-mass of 3rd piece,\bar v_1-velocity of first piece(-23\dot i \ m/s) and \bar v_2 as velocity of 2nd piece (-23\dot j \ m/s)

Let \bar v_3 be velocity of 3rd piece=?

#Vessel is at rest before explosion. Considering conservation of linear momentum:

m\bar v_1 +m\bar v_2 +3m \bar v_3=0   #Dividing both sides by m, m\neq 0

\bar v_1+ \bar v_2 +3\bar v_3=0\\3\bar v_3=-(\bar v_1 +\bar v_2)\\\bar v_3=-\frac{1}{3}(\bar v_1 +\bar v_2)

#Plug the\bar v_1 ,\bar v_2  values:

\bar v_3=-\frac{1}{3}(-23\dot i -23\dot j)=\frac{1}{3}(23\dot i +23\dot j)

#So the magnitude of the third piece is:

|\bar v_3|=\sqrt{(23/3)^2+(23/3)^2}\\=10.84m/s

Magnitude of the 3rd piece is 10.84 m/s

b. To find direction of the magnitude (as an angle relative to the x-axis), we find \angle \theta. The angle is obtained by getting the tan inverse as:

\theta=tan^-^1(\frac{23/3}{23/3})\\=45\textdegree

-The direction of the magnitude (angle relative to the x-axis) is 45°

6 0
3 years ago
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