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3 years ago

An object at a distance of 6400km from the centre

Physics

1 answer:

Fittoniya [83]3 years ago

6 0

Answer:

12.5N

Explanation:

From newton law of universal gravitation F= GmM/d2.

that means Force is inversely proportional to the square of the distance apart.

F1= 50N, d1=6400km

F2=?, d2=12800km

F1/F2=d2×d2/d1×d1 so we have 50/F2= 12800×12800/6400×6400...F2=6400×6400×50/(12800×12800)=12.5N

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Answer:

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Explanation:

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v = speed of the particle
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A proton has mass number 1.

Thus, the relative masses of an alpha particle and a proton are:

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For the kinetic energies you find:

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$\dfrac{1eV}{4eV}=\dfrac{4\times v_\alpha^2}{1\times v_p^2}\\\\\\\dfrac{v_p^2}{v_\alpha^2}=16\\\\\\\dfrac{v_p}{v_\alpha}=4$

Thus:

$\dfrac{m_\alpha}{m_p}=4=\dfrac{v_p}{v__\alpha}$

$m_\alpha v_\alpha=m_pv_p$

From de-Broglie equation, λ = h/(mv)

$\dfrac{\lambda_p}{\lambda_\alpha}=\dfrac{m_\lambda v_\lambda}{m_pv_p}=\dfrac{1}{1}=1:1$

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