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zzz [600]
4 years ago
14

An object at a distance of 6400km from the centre

Physics
1 answer:
Fittoniya [83]4 years ago
6 0

Answer:

12.5N

Explanation:

From newton law of universal gravitation F= GmM/d2.

that means Force is inversely proportional to the square of the distance apart.

F1= 50N, d1=6400km

F2=?, d2=12800km

F1/F2=d2×d2/d1×d1 so we have 50/F2= 12800×12800/6400×6400...F2=6400×6400×50/(12800×12800)=12.5N

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Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides o
jekas [21]

Answer: The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet.

Explanation:

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3 0
3 years ago
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What is the momentum of a 75-kilogram ice skater gliding across the ice at a speed of 13 m/s? ____ kg-m/s
Damm [24]
Momentum = Mass*Velocity

Momentum = 75*13
Momentum = 975

The answer is 975 kg-m/s
Hope you get help
7 0
4 years ago
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A 240-volt, 2-amp motor is connected to a three-wire, 120/240-volt system. Connected between the black wire and neutral are four
pantera1 [17]

Answer:

(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is  15.36 A (iv) when 240 volt were disconnected current  in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A

Explanation:

Solution

The current drawn by one amp is

I =P/V

I =200/120

I= 1.67 A

(i) The current flow in the black wire  is

IBK = 4 * 1.67 A + 1A + 2A

IBK = 9.67 A

(ii) Current flow in the red wire is

IRD = 3 * 1.67 A + 1.67 A + 1A + 2A

= 8.68A + 1 A = 9.68 A

Note: Kindly find an attached copy of part of the solution to the given question above.

6 0
4 years ago
Two spheres are made of wood - the first is a variety of wood whose density is equal to that of water, while the second is of a
ki77a [65]

Answer:

The buoyant force experienced by a body is equal to product of unit weight of liguid in which the the objevt is immersed and the volume of liquid replaced by the object.

In the given scenario, bothe the spheres have equal volume and are fully submerged in water. Therefore, the buoyant force experienced by both the spheres will be equal.

5 0
4 years ago
A neutron star is an extremely dense, rapidly spinning object that results from the collapse of a massive star at the end ofits
Westkost [7]

Answer:

(a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Explanation:

Given that,

Mass of neutron M_{n}= 13M_{s}

Density of neutron \rho=4.8\times10^{17}\ kg/m^3

(a). We need to calculate the rotational inertia

Using formula of rotational inertia  for sphere

I=\dfrac{2}{5}MR^2...(I)

We know that,

\rho=\dfrac{M}{V}

Put the value of volume

\rho=\dfrac{3M_{n}}{4\pi R^3}

R^2=(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value of R in equation (I)

I=\dfrac{2}{5}\times M_{n}\times(\dfrac{3M_{n}}{4\pi\rho})^{\frac{2}{3}}

Put the value into the formula

I=\dfrac{2}{5}\times(13\times2\times10^{30})^{\frac{5}{3}}\times(\dfrac{3}{4\pi\times(4.8\times10^{17})})^{\frac{2}{3}}

I=5.72\times10^{39}\ kg m^2

The rotational inertia is 5.72\times10^{39}\ kg m^2.

(b). We need to calculate the magnitude of the magnetic torque

Using formula of torque

\tau=I\times \alpha

Put the value into the formula

\tau=5.72\times10^{39}\times5.6\times10^{-5}

\tau=3.20\times10^{35}\ N-m

The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

Hence, (a). The rotational inertia is 5.72\times10^{39}\ kg m^2

(b). The magnitude of the magnetic torque is 3.20\times10^{35}\ N-m

4 0
3 years ago
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