1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
devlian [24]
3 years ago
11

Space vehicles traveling through Earth's radiation belts can intercept a significant number of electrons. The resulting charge b

uildup can damage electronic components and disrupt operations. Suppose a spherical metallic satellite 1.7 m in diameter accumulates 3.1 µC of charge in one orbital revolution. (a) Find the resulting surface charge density. (b) Calculate the magnitude of the electric field just outside the surface of the satellite, due to the surface charge.
Physics
1 answer:
Goshia [24]3 years ago
7 0

Answer:

(a) σ = 3.41*10⁻7C/m^2

(b) E = 38,530.1 N/C

Explanation:

(a) In order to calculate the resulting surface charge density, you use the following formula:

\sigma=\frac{Q}{S}     (1)

σ: surface charge density

Q: charge of the satellite = 3.1 µC = 3.1*10^-6C

S: surface area of the satellite

The satellite has a spherical form, then, the area of the surface is given by:

S=4\pi r^2     (2)

r: radius of the satellite = d/2 = 1.7m/2 = 0.85m

You replace the equation (2) into the equation (1) and solve for the surface charge density:

\sigma=\frac{3.1*10^{-6}C}{4\pi (0.85m)^2}=3.41*10^{-7}\frac{C}{m^2}

The surface charge density acquired by the satellite on one orbit is 3.41*10⁻7C/m^2

(b) The electric field just outside the surface is calculate d by using the following formula:

E=k\frac{Q}{R^2}      (3)

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

R: radius of the satellite = 0.85m

E=(8.98*10^9Nm^2/C^2)\frac{3.1*10^{-6}C}{(0.85m)^2}=38530.1\frac{N}{C}

The magnitude of the electric field just outside the sphere is 38,530.1 N/C

You might be interested in
/
Mumz [18]
No se ha da han dicho nada más de lo dicho y han ido de vuelta y han dicho nada más de que se pueda hacer el favor del niño
4 0
2 years ago
Read 2 more answers
What problems do pathogens cause in our society?
kotegsom [21]

Pathogens are microorganisms that cause infectious diseases. Bacteria and viruses are the main pathogens in the world today.

The major problem that pathogen cause in society is that they are the agents of infection and disease. 

An infection results when a pathogen invades the body and begins growing within a host.  A disease results when tissue function is impaired due to an infection.

Due to diseases, affected people can not work  which negatively affects the economy, and the sick may end up dying causing a lot of grief, and robbing society of a father, a mother or child.

The government has to put money aside for health care which would otherwise have been used for other things to help the society.

3 0
3 years ago
A laser beam with a frequency of 180 Hz forms an 8 m standing wave with 10 nodes.
DIA [1.3K]

Answer:33

Explanation:

F = frequency

N =  Node count

w = wave lenght

v = wave velocity

L = distance wave traveled

First find wave length of laser

w = (2/(N))*(L)

w = (2/(10))*(8)

w = 1.6

then using (w), find velocity

V =  (w)(F)

V = (1.6)*(108)

V = 288

Plug in V and the new frequency to solve for new node count

F = NV/2L

(600) = (N)*(288) / 2 * (8)

(N) = 33.33

there are 33 nodes

8 0
3 years ago
Two airplanes leave an airport at the same time. The velocity of the first airplane is 660 m/h at a heading of 28.6 ◦ . The velo
Vesnalui [34]
Can someone help me with a question? At the local ski park, James earns 519.36 for working 32 hours. Create a double number line to identify the amount of money he would make for 1, 8 and 40 hours of work?
5 0
3 years ago
a waves amplitude is 0.5 meters. If the amplitude is increased to 1 metro, how does its energy change
marysya [2.9K]

Answer:

The energy becomes 4 times greater.

Explanation:

We know that the energy of a wave is proportional to the square of its amplitude

E ∝ Amplitude^2

Since the original amplitude = 0.5 m

and the new amplitude becomes = 1 m

We are doubling the amplitude. This means that the new energy will be affected by a factor of 4

E_new  ∝ (2*Amplitude)^2  =

E_new ∝ 4*(Amplitude)^2  

E_new  = 4*E

5 0
3 years ago
Other questions:
  • If a sprinter’s mass is 60 kg, how much forward force must be exerted on the sprinter to make the sprinter accelerate at 0.8 m/s
    12·2 answers
  • How do objects and substances have kinetic energy??<br><br> I need help ASAP!!
    7·1 answer
  • What is 300N divided by 25 kg?
    15·1 answer
  • How do i figure out this question?
    7·2 answers
  • A soccer ball rolls to a stop of 21 m/s with a deceleration of -2.0 m/s. How far does it roll until it stops?
    14·2 answers
  • What is 1 and 2 I need it asap
    14·1 answer
  • A rope with a mass density of 1 kg/m has one end tied to a vertical support. You hold the other end so that the rope is horizont
    14·1 answer
  • How do weathering and deposition differ
    12·1 answer
  • A 1200 kg car traveling east at 4.5 m/s crashes into the side of a 2100 kg truck that is not moving. During the collision, the v
    8·1 answer
  • Ini adalah anjing<br>this is a dog<br><br>​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!