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Hitman42 [59]
3 years ago
10

A people-moving conveyor-belt moves a 600-newton person a distance of 100 meters through the airport.

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
In a), no work is done to move horizontally 'across" gravity. In b), he does (m) (g) (h) = (100)(9.8)(1) = 980 joules of work to lift the bag, and then no more work is done by the belt to move both of them horizontally.
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The closure temperature represents the point when ________. A. a magma cools to the point where minerals begin to crystallize B.
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The closure temperature represents the point when isotopes are no longer free to move out of a crystal lattice.

Answer: Option C

<u>Explanation:</u>

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5 0
3 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 9.0 s. At thi
sertanlavr [38]

Answer

given,

angular speed of the tub = 5 rev/s

time = 9 s

he tub slows to rest  =  15.0 s

the angular acceleration

\omega_f - \omega_i = \alpha t

\alpha = \dfrac{5-0}{9}

\alpha = 0.556 rev/s^2

angular displacement

\theta_1 = \omega_i \ t + \dfrac{1}{2}\alpha t^2

\theta_1 = \dfrac{1}{2}\times 0.556 \times 9^2

\theta_1 = 22.52 rev

\theta_1 = 23 rev

case 2

now,

\omega_i = 5 rev/s

\omega_f = 0 rev/s

time = 15 s

the angular acceleration

\omega_f - \omega_i = \alpha t

\alpha = \dfrac{0-5}{15}

v\alpha =-0.333 rev/s^2

angular displacement

\theta_2 = \omega_i \ t + \dfrac{1}{2}\alpha t^2

\theta_2 =5\times 15 -\dfrac{1}{2}\times 0.333 \times 15^2

\theta_2 = 37.875 rev

\theta_2 =38 rev

total revolution in 24 s

= 23 + 38

= 62 revolution

8 0
3 years ago
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