Answer:
Tyrell is in the lead by 2 points.
Step-by-step explanation:
Example:
Imagine they both started at 10 points. If Parline lost 5 points (10 - 5) while Tyrell lost 3 points (10 - 3), then it is clear that Tyrell's points (7 remainings) are more than Parline's points (only 5 remainings). Hence, Tyrell is in the lead by 2 points.
Answer:
(a) V = 51200 cubic cm
(b) V' = 38912 cubic cm
(c) V'' = V - V' = 12288 cubic cm
Step-by-step explanation:
side of the square base, s = 32 cm
height, h = 50 cm
height of cake mixture, h' = 38 cm
(a) The capacity of the tin is the volume.
Capacity of tin, V = s x s x h = 32 x 32 x 50 = 51200 cubic cm
(b) The volume of the cake mixture is
V' = s x s x h'
V' = 32 x 32 x 38 = 38912 cubic cm
(c) Volume of unoccupied space is
V'' = V - V' = 51200 - 38912 = 12288 cubic cm
Answer:
The 3rd and 4th option
Explanation:
A function only works when the input (x) only has one output (y).
The first, second, and the last option has the input has two or more outputs.
Fun Fact:
It is okay for the outputs to have more then in input, but not okay for the input to have more then one output.
I hope this help and have a nice day :)
Answer:
Quadratic Formula
so
x = -5
and
x = 0.5
Step-by-step explanation:
Whenever you see a problem in this form, which you will see a lot of, you can try to factor it or use the "least squares" method or what have you, but those won't always work, unfortunately.
Fortunately, the quadratic formula will never fail you with quadratic expressions.
This is the Quadratic Formula
a is the the number on the variable with the exponent ^2
b is the number on the variable with no exponent
c is the third number
a and b cannot be equal to 0; c can be
Since we're looking for a number with an equation that has a square root in it, we're going to get two answers. These two answers come from the radical being separately added AND subtracted from the radical. It's basically two problems.
Plugging in our numbers to this equation gives us x values of -5 and 0.5. This will always work with polynomials with factors of ^2 in them.
If you have a TI-84 calculator or newer, there's a tool on it that will factor polynomials like this one for you just by giving it the numbers.
<span>13-((4/5)+(6/8))
Make your fractions have common denominators
</span>13-((32/40)+(30/40))
Add your fractions and simplify
13-(62/40)
or
13-(31/20)
or
13-(1 11/20)
Then turn 13 into a fraction with a common denominator! Im going to use the second fraction method (31/20)
13 written as a fraction is 13/1, its LCD with 31/20 is 20. I now multiply the top and bottom by 20
260/20
Now I rewrite the problem again
(260/20)-(31/20)
Which equals
229/20!
This is your unsimplified answer
Finally you simplify and get
11 9/20
