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3 years ago

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Physics

1 answer:

Ludmilka [50]3 years ago

6 0

Answer:

Explanation:

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In a random sample of 200 students from Northern State University, 150 said that they own an Therefore, probably at least 50% of

kirza4 [7]

Answer:

No fallacy

Explanation:

The statement that at least 50% of the students at Northern State own an iPod is best categorized as no fallacy.

This statement is very true and consistent with the facts presented in the passage.

A fallacy is a mistaken belief usually based on biased arguments.

Total number of students sampled = 200

Number of iPod owners = 150

Percentage of iPod owners = $\frac{number of iPod owners}{Number of sample}$ x 100

Percentage of iPod owners = $\frac{150}{200}$ x 100 = 75%

We see that it is consistent to say that at least, 50% of the students in the sample are iPod owners.

6 0

3 years ago

An object of mass 100kg is released from rest and falls through a distance of 10m.what is the work done by gravity

aleksandr82 [10.1K]

Answer:

Mass = 100 kg

Acceleration due to gravity = 9.8m/s

Height = 10 m

Work done = mgh

= 100 x 9.8 x 10

= 9800 J

Hope this helps!

8 0

3 years ago

It is important to organize your data because

Natasha_Volkova [10]

The second one is false

5 0

4 years ago

Vilket är det modernaste förvarings materialet?

Zinaida [17]

<span>Det är behållaren med lock.</span>

8 0

3 years ago

A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo

Nina [5.8K]

The work done is $2.8125 \times 10^{5} \mathrm{J}$

Work Done = Change in Kinetic Energy (ΔKE)

<u>Explanation</u>

In first 1 hour it travels 72 km

So, Velocity = $\frac{\text { distance }}{\text { time }}=\frac{72}{1} k m / h=72 \mathrm{km} / \mathrm{h}=\frac{72000}{3600} \mathrm{m} / \mathrm{s}=20 \mathrm{m} / \mathrm{s}$

or, Initial Velocity (u) = 20 m/s

Similarly for the next hour it covers 90 km

So, Velocity = $\frac{\text { distance }}{\text { time }}=\frac{90}{1} k m / h=90 \mathrm{km} / \mathrm{h}=\frac{90000}{3600} \mathrm{m} / \mathrm{s}=25 \mathrm{m} / \mathrm{s}$

or, Final Velocity (v) = 20 m/s

Work done = Change in Kinetic Energy (ΔKE)

Work done = ΔKE = $\frac{1}{2} m v^{2}-\frac{1}{2} m u^{2}$

ΔKE = $\frac{1}{2} m\left(v^{2}-u^{2}\right)=\frac{1}{2} \times\left(2.5 \times 10^{3}\right) \times\left(25^{2}-20^{2}\right)$

= $\frac{2500 \times(625-400)}{2}=\frac{2500 \times 225}{2}=\frac{562500}{2}$ = 281250 joule

= $2.8125 \times 10^{5} \mathrm{J}$

4 0

3 years ago