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maksim [4K]
3 years ago
5

The potential energy U as a function of the position x of an object is given by U (x) = - 400/x, where U is in joules and x is i

n meters. The object is released from rest at position x = 30 m and is free to move along the x-axis. When the object has moved a distance of 10 m from its initial position, the magnitude of the force associated with this potential energy function is
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Hi there!

We know that:

F = -dU/dx, so:

U = -400/x

dU/dx = 400/x² (Take the derivative)

F = -dU/dx = -400/x²

Finding the force at 10m away from the starting point (30m), means a position of 40m. So:

F = -400/(40²) = -0.25 N

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3 years ago
A rocket in deep space has an exhaust-gas speed of 2000 m/s. When the rocket is fully loaded, the mass of the fuel is five times
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At the time of burning half of the fuel the mass ratio is that the current mass is    

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3 0
3 years ago
A 15-kg block at rest on a horizontal frictionless surface is attached to a very light ideal spring of force constant 450 N/m. T
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7 0
3 years ago
A particle that is moving along a straight line accelerates from 40 cm/s to 20 cm/s in 5.0 s and then has a constant acceleratio
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Answer:

Average speed,  v_{avg}=43.33\ \rm cm/s

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4 0
4 years ago
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