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3 years ago

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The speed of a car decreases uniformly as it passes a curve point where normal component of acceleration is 4 ft/sec2. If the ca

r total acceleration of 5ft/sec2 is the same as it passes a hump, the tangential component of acceleration is _______________ ft/sec2.

1 answer:

belka [17]3 years ago

8 0

Answer:

45

Explanation:

ft/sec2

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A 1.7m long barbell has a 20kg weight on its left and a 35kg weight on its right. (a) If you ignore the weight of the bar itself

Levart [38]

Answer:

(a) 1.08 m

(b) 1.06 m

Explanation:

<u>Step 1:</u> calculate the center of gravity from 20kg mass

Let the center of gravity from 20kg mass = X

Applying the principle of moment; clockwise moment = ant-clockwise moment

20*X = 35*(1.7-X)

20X = 59.5 - 35X

55X = 59.5

X = 59.5/55

X = 1.08 m

Ignoring the weight of the bar, the center of gravity is 1.08m from left end of the barbell.

<u>Step 2:</u> calculate the center of gravity from 20kg mass, if the 8.0kg mass of the barbell in considered.

Applying the principle of moment

$(20*X)+\frac{X}{2}(\frac{8}{1.7}) = 35(1.7-X) + (\frac{1.7-X}{2})(\frac{8}{1.7})$

$20X + 2.353X = 59.5 -35X +2.353(1.7-X)$

20X +2.353X = 59.5 -35X + 4 - 2.353X

59.706X = 63.5

X = 63.5/59.706

X = 1.06 m

considering the weight of the bar, the center of gravity is 1.06m from left end of the barbell.

4 0

2 years ago

A ball is thrown vertically upward with a speed of 12.0 m/s. (<br> a. How high does it rise?

sdas [7]

It rises till all of its Kinetic energy is converted into potential energy.

so, mgh=(1/2)m(v^2)

so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m

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2 years ago

Which part of the planet had the highest concentration of ozone in 1989?

Nat2105 [25]

Answer:

earth

sorry I need points but I don’t know the answer again I’m really sorry

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2 years ago

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect a

rjkz [21]

Answer:

The speed will be "18km/s". A further explanation is given below.

Explanation:

According to the question, the values are:

Wavelength,

$\lambda = 656.46 \ nm$

$\Delta \lambda = 0.04$

$c=3\times 10^8$

As we know,

⇒ $\frac{\Delta \lambda}{\lambda} =\frac{v}{c}$

On substituting the values, we get

⇒ $\frac{656.46}{0.04} =\frac{v}{3\times 10^8}$

⇒ $v=\frac{656.46}{0.04} (3\times 10^8)$

⇒ $=16411.5\times 3\times 10^8$

⇒ $=18280 \ m/s$

or,

⇒ $=18 \ km/s$

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2 years ago

How do scientists use the doppler effect to understand the universe?

Nadusha1986 [10]

For the First answer, It would be "A"

The for the next one the answer is "C"

I hope this helps. :)

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2 years ago

Read 2 more answers