Answer:
q2 = -1.61*10^-5 C.
Explanation:
It was given that,
F = 0.985N
q1 = +8.40 X10-6 C
q2 = ?
r = 1.11 m
k = 9 x 10^9 (standard)
It generally follows that, if force is attractive, charge will be negative.
force, F = kq1q2/r^2
0.985 = 9*10^9*8.40*10^-6*q2/1.11^2
75600q2 = 0.985*1.11^2
75600q2 = 1.2136
q2 = 1.2136/75600 = 1.60529
q2 = -1.61*10^-5 C.
No it will not because F will equal 3 not 0
If im not mistaken the truck traveled 216 meters.
So, If the resistance decreases, then the current increases. Assume voltage is constant.
If the voltage increases, then the current increases. Assume resistance is constant.
Explanation:
According to the ohm's law; I = V/R;
- If the resistance decreases the current increases assuming that the voltage is constant
- if the voltage increases, then the current increases assuming that the resistance is constant.
Based on Ohm's law, we know that the current through a metallic conductor is directly proportional to the voltage across the ends.
From the relationship;
I =
we see that V = IR
These equations affirms that
- If the resistance decreases the current increases assuming that the voltage is constant based on the second equation
- if the voltage increases, then the current increases assuming that the resistance is constant based on the first equation.
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Electric circuit brainly.com/question/10421964
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Answer:
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